Answer:
D You got it right. 65% 5/8 3/5 0.5
If the right box is the original it would be B and D, however if it is the left box being the original, it would be just B.
Rewriting the left hand side,
csc²t - cost sec t
= (1/sin²t)-(cost)(1/cost)
= 1/sin²t - 1
= 1/sin²t - sin²t/sin²t
= (1-sin²t)/sin²t
= cos²t/sin²t
= cot²t
- The rate of the hose with the large diameter is:
Answer: A). 1/9.
- What is the unknown in the problem?
Answer: C). the time it takes for the hoses working together to fill the pool
-What part of the job does the hose with the large diameter do?
Answer: B). x/9
Answer:
x = y = 
Step-by-step explanation:
= 90
