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AnnZ [28]
3 years ago
8

Which of the following Triangle cases cannot be solved, using either the law of cosines or law of sines

Mathematics
2 answers:
hodyreva [135]3 years ago
8 0
The answer is D. You cannot use aaa
gizmo_the_mogwai [7]3 years ago
5 0

Answer:

(D) AAA

Step-by-step explanation:

Law of cosines: Law of cosines are mostly used in those cases which includes two sides and one included angle.

Thus, SAS and SSS triangle cases can be solved by the Law of cosines.

Law of sines: Law of sines can be used in those cases which includes one side and an angle opposite to  that angle.

Thus, SAA triangle case can be solve by the law of sines.

Only AAA is the only triangle case which can neither be solved by Law of cosines nor by Law of sines.

Thus, Option D is correct.

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Please help me.<br> Round 34,699 to the nearest ten thousand. ASAP
harina [27]
Your number is 34,699 right and if anything is 5000 or over round ahead so it is 30,000
7 0
3 years ago
Read 2 more answers
Solve
NISA [10]

Answer:

r = 0.01

Step-by-step explanation:

In order to find r we have to square both sides of the equation

0.1 =  \sqrt{r} \\  {0.1}^{2}  =  { \sqrt{r} }^{2}

The *square root* sign cancels out the *squared* sign therefore:

{0.1}^{2}  = r \\ 0.01 = r

6 0
2 years ago
Please help fast! 25 points and brainliest!!
Firlakuza [10]

Answer:

The answer is

<h2>9x³ - 11x² - 7x</h2>

Step-by-step explanation:

f(x) = 36x^5 − 44x⁴ − 28x³

g(x) = 4x²

To find f(x) / g(x) Divide each term of f(x) by g(x)

That's

\frac{f(x)}{g(x)}  =  \frac{ {36x}^{5} -  {44x}^{4}  -  {28x}^{3}  }{ {4x}^{2} }  \\  \\  =  \frac{ {36x}^{5} }{ {4x}^{2} }  -  \frac{ {44x}^{4} }{ {4x}^{2} }  -  \frac{ {28x}^{3} }{ {4x}^{2} }  \\  \\  =  {9x}^{3}  -  {11x}^{2}  - 7x

Hope this helps you

3 0
3 years ago
A group of friends chartered a deep-sea fishing boat out of destin, fl. the graph below represents the total cost, in dollars, o
Elenna [48]

The difference in price per passenger for a group of 16 versus a group of 10 is $26.25

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more number and variables.

From the graph:

The cost for a group of 16 friends is $2500, while for a group of 10 friends is $1300.

Cost per passenger for 16 friend = $2500 / 16 = $156.25

Cost per passenger for 10 friend = $1300 / 10 = $130

The difference in price = $156.25 - $130 = $26.25

The difference in price per passenger for a group of 16 versus a group of 10 is $26.25

Find out more on equation at: brainly.com/question/2972832

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3 0
2 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
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