3 years ago

How do I do this? My teacher makes these problems very confusing...

Mathematics

1 answer:

prohojiy [21]3 years ago

8 0

You substitute the equation and see if it works. Also, the first one that you answered is wrong.

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What is the 101st term in the sequence 997, 989, 981, ...?

melamori03 [73]

Answer: first option.

Step-by-step explanation:

Find the common difference d of the arithmetic sequence:

$d=a_n-a_{(n-1)}\\d=989-997\\d=-8$

Then the formula for the 101st term is the shown below:

$a_n=a_1+(n-1)d$

Where:

$a_1=997\\d=-8\\n=101$

Substitute values into the formula. Therefore, you obtain:

$a_n=997+(101-1)(-8)=197$

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3 years ago

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fiasKO [112]

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3 years ago

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sveticcg [70]

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Step-by-step explanation:

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3 years ago

I’ll give the bralyist to the first correct answer

ArbitrLikvidat [17]

Answer:

The answer is 2

From the function when the input is 2 the output is -7. The inverse reverses the order so the input will be -7 and the output will be 2.

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3 years ago

Instructions: Factor 715 as a product of primes.

Drupady [299]

Answer:

{1, 5, 143}

Step-by-step explanation:

715 is evenly divisible by 5, so one factor of 715 is 5 and the next is 715/5, or 143. 143 is not factorable further. Thus, the factors of 715, in ascending order, are 1, 5 and 143.

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3 years ago