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3 years ago

PLEASE HELP TIMED TEST HELP!!!!!!!!

Mathematics

1 answer:

Lelu [443]3 years ago

6 0

Answer:

Step-by-step explanation:

The equations that she wrote are

6x+8y=133

2x=y

The following statements about the system are true

1.Since the cost for each pie is $5 and $9, the first equation should be 5x+9y=133

5. The second equation is correct because there are more 6 inch pies and 2 times a number is always more.

The following statements are wrong because,

2. Because there was no relationship between the number of pipes sold and the size of each pipe.

3. x=2y shows that there are more 8 inches pipes

4. 6 and 8 are just size descriptions. It is only the cost of each size of pipe that related to the total cost

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For the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled b

dmitriy555 [2]

Answer:

2019.

Step-by-step explanation:

We have been given that for the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled by $H = 1,500e^{0.053t}$ where t is the number of years past 2000.

To find the year in which national health care expenditures expected to reach $4.0 trillion (that is, $4,000 billion), we will substitute $H=4,000$ in our given formula and solve for t as:

$4,000= 1,500e^{0.053t}$

$\frac{4,000}{1,500}=\frac{ 1,500e^{0.053t}}{1,500}$

$\frac{8}{3}=e^{0.053t}$

$e^{0.053t}=\frac{8}{3}$

Take natural log of both sides:

$\text{ln}(e^{0.053t})=\text{ln}(\frac{8}{3})$

$0.053t\cdot \text{ln}(e)=\text{ln}(\frac{8}{3})$

$0.053t\cdot (1)=0.9808292530117262$

$\frac{0.053t}{0.053}=\frac{0.9808292530117262}{0.053}$

$t=18.506212320$

So in the 18.5 years after 2000 the expenditure will reach 4 trillion.

$2000+18.5=2018.5$

Therefore, in year 2019 national health care expenditures are expected to reach $4.0 trillion.

7 0

3 years ago

Point A is plotted at (-5, 3)

Diano4ka-milaya [45]

Answer:

quadrant 1

Step-by-step explanation:

quadrant 1 is (-,+)

5 0

2 years ago

At 82°F, a certain insect chirps at a rate of 61 times per minute, and at 91°F, they chirp 124 times per minute. Write an equati

Ganezh [65]

Answer:

$y=7x-513$

Step-by-step explanation:

Let

x----> the temperature in degrees Fahrenheit

y ---->insect chirping rate in times per minute

we have the ordered pairs

(82,61) and (91,124)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{124-61}{91-82}$

$m=\frac{63}{9}=7$

step 2

Find the equation of the line

we know that

The equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=7$ ---> the units are chirps per minute/degree F

take the point (82,61)

substitute and solve for b

$61=7(82)+b$

$61=574+b$

$b=-513$

substitute

$y=7x-513$

4 0

2 years ago

What is the area of this figure?

Vladimir79 [104]

Answer:

<em>97 square miles</em>

Step-by-step explanation:

Let us divide this figure into rectangles, each of set dimensions;

$Dimensions of Rectangle A - Height ; 2 mi, Length ; 9 mi\\Area of Rectangle A - Height * Length = 2 mi * 9 mi = 18 square miles,\\\\Dimensions of Rectangle B - Height ; 2 mi + 5 mi = 7 mi, Length ; 5 mi\\Area of Rectangle B - Height * Length = 7 mi * 5 mi = 35 square miles,\\\\Dimensions of Rectangle C - Height ; 4 mi + 5 mi + 2 mi = 11 mi, Length ; 4 mi,\\Area of Rectangle C - Height * Length = 11 mi * 4 mi = 44 square miles,\\\\Area of Figure = 18 + 35 + 44 = 97 square miles$

<em>Solution; 97 square miles</em>

4 0

2 years ago

A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).

JulsSmile [24]

The answer is 16.8 units

7 0

2 years ago

Read 2 more answers