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Over [174]
3 years ago
11

If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the

Chemistry
1 answer:
Alina [70]3 years ago
3 0

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

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5 0
3 years ago
Explain why an insoluble compound added to water is considered a nonelectrolyte.
DaniilM [7]

Explanation:

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How many electrons are shared in the Lewis structure
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3 0
3 years ago
How can a flame test identify an unknown element?
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6 0
3 years ago
I will give brainliest!! How long is the pencil? Make sure to use the appropriate amount of significant figures.
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Answer: Option (c) is the correct answer.

Explanation:

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