Answer:
Reduction of Aldehydes and Ketones. Hydride reacts with the carbonyl group, C=O, in aldehydes or ketones to give alcohols. ... Reduction of ketones gives secondary alcohols. The acidic work-up converts an intermediate metal alkoxide salt into the desired alcohol via a simple acid base reaction.
The carbon atom of a carboxyl group is in a relatively high oxidation state. Diborane, B2H6, reduces the carboxyl group in a similar fashion. ... Sodium borohydride, NaBH4, does not reduce carboxylic acids; however, hydrogen gas is liberated and salts of the acid are formed.
Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.
A secondary alcohol can be oxidised into a ketone using acidified potassium dichromate and heating under reflux. The orange-red dichromate ion, Cr2O72−, is reduced to the green Cr3+ ion. This reaction was once used in an alcohol breath test.
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Answer:
Explanation:1 mole is equal to 1 moles CaCO3, or 100.0869 grams.
Answer:
There will be weight, there will be volume, there will be height
Explanation:
Good questions,ideas,and observations
Q1. An inorganic compound is a compound where the main constituent or substance is not that of Carbon but predominantly other elements, such as I, N etc. An organic compound is one where the main substituent or main element, the element found in much greater amounts would be Carbon.
Q2. Water is considered a very good solvent, because of its ability to dissolve well with mostly all other polar compounds, and produce ions from those ionic compounds.
A. Hydrogen atoms
B. Oxygen atom.
