Answer:
Despite their similar use in wastewater treatment as flocculants and coagulants, FeCL2 and FeCl3 have different<u> molecular formula</u>,<u> colours</u>, and <u>common names
</u>
Explanation:
<u>FeCl3:
</u>
• Purple-red colour as anhydrous crystal and yellow in solution
• Used as catalyst
• In Iron (III) chloride the iron atoms have lost three electrons so you need three chlorine atoms, hence the chemical formula FeCl3.
• Common name: <em>Ferric chloride
</em>
<u>FeCl2:
</u>
• In Iron (II) chloride the iron atoms have lost two electrons so you need two chlorine atoms, hence the chemical formula FeCl2.
• Difference in formula means different molecular masses as well.
• White colour as anhydrous salt and green in solution
• Common name: <em>Ferrous Chloride
</em>
Answer:
Yes aluminum is reactive than copper
Answer:
React it with CH₃MgBr and work up the product with saturated ammonium chloride solution
Explanation:
Grignard reagents convert esters into tertiary alcohols.
The general equation is
![\text{RCOOR}' \xrightarrow[\text{2. H}^{+}]{\text{1. R$^{\prime \prime}$MgBr}}\text{RR$_{2}^{\prime \prime}$C-OH}](https://tex.z-dn.net/?f=%5Ctext%7BRCOOR%7D%27%20%5Cxrightarrow%5B%5Ctext%7B2.%20H%7D%5E%7B%2B%7D%5D%7B%5Ctext%7B1.%20R%24%5E%7B%5Cprime%20%5Cprime%7D%24MgBr%7D%7D%5Ctext%7BRR%24_%7B2%7D%5E%7B%5Cprime%20%5Cprime%7D%24C-OH%7D)
The Grignard reagent in this synthesis is methylmagnesium bromide. You prepare it by reacting a solution methyl bromide in anhydrous ether with magnesium and a few crystals of iodine.
The reaction consumes 3 mol of CH₃MgBr per mole of dimethyl carbonate, and everything happens in the same pot.
Acid workup of the product usually involves the addition of a saturated aqueous solution of ammonium chloride and extraction with a low-boiling organic solvent.
The mechanism involves:
Step 1. Nucleophilic attack and loss of leaving group
(a) The Grignard reagent attacks the carbonyl of dimethyl carbonate, followed by (b) the loss of a methoxide leaving group.
Step 2. Nucleophilic attack and loss of leaving group
(a) A second mole of the Grignard reagent attacks the carbonyl of methyl acetate, followed by (b) the loss of a methoxide leaving group.
Step 3. Nucleophilic attack and protonation of the adduct.
(a) A third mole of the Grignard reagent attacks the carbonyl of acetone, followed by (b) protonation of the alkoxide to form 2-methylpropan-2-ol.
Answer:
I screenshot and expained here
https://screenshot.best/A7QIKV.lnk
Explanation:
Answer:
B. burning a piece of wood
Explanation:
The Chemical Would Be The Air Coming From The Wood While Burning It
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