Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:
The probability of both failing the test and being unfit is:
Hence, the conditional probability is:
0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
The answer to this question is 5z+9
Answer:
See Explanation
Step-by-step explanation:
Required
Determine any equation where n = 6
Add n to both sides
<em></em><em> ----- This is 1 equation</em>
Multiply both sides by n
<em></em><em> ----- This is another</em>
<em></em>
Add 5n to both sides
<em></em><em> ---- This is another</em>
Subtract 10 from both sides
<em></em><em> --- This is another</em>
<em>You can have as many equations as possible</em>
The answer is 44, to solve, add 39 to 5
Answer:
Three times a number plus 16
To solve this, we simply need to break down the words and turn each part into an equation.
"Three times"
This shows that we will be multiplying 3 and something.
3*
"a number"
This shows that the number we will be multiplying 3 by is "n," which represents a number.
3*n or 3n
"plus 16"
This shows we will be adding 16 to the rest of the equation.
3n+16
Using the logic above, we can see that the equation to represent this is 3n+16.