The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane
Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
Answer: Sorry to be rude but could I see the question? Thank you and when I see it I will take a look at it.
Answer: False
Step-by-step explanation:
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