Question

A laser beam is transmitted with a "width" of .0008 degrees and

Answer 1

Answer:

Object will be at a distance of 358098.6 km from the source

Step-by-step explanation:

We have given angle = 0.0008 degree $=\frac{0.0008\times \pi }{180}=4.444\times 10^{-6}\pi$

Radius is given = 2.50 km

Linear size of the object will be equal to diameter

So linear size = 2.5×2 = 5 km

We know that linear size $=distance \times \Theta$

So $5=d\times 4.444\times 10^{-6}\pi$

d = 358098.6 km