<h2>Answer </h2>
Amount (A) = P[1 + (r/100)]n
Principal (P) = ₹ 26400
Time period (n) = 2 years 4 months
Rate % (R) = 15% compounded annually
<h3>Steps </h3>
First, we will calculate Compound Interest (C.I) for the period of 2 years
A = P[1 + (r/100)]n
= 26400[1 + (15/100)]²
= 26400[(100/100) + (15/100)]²
= 26400 × 115/100 × 115/100
= 26400 × 23/20 × 23/20
= 26400 × 1.3225
= 34914
C.I. = A - P
= 34914 - 26400
= 8514
Now, we will find Simple Interest (S.I) for the period of 4 months
Principal for 4 months after C.I. for 2 years = ₹ 34,914
<h3>We know that ,</h3>
S.I = PRT/100
Here T = 4 months = 4/12 years = 1/3 years
S.I. for 4 months = (1/3) × 34914 × (15/100)
= (1/3) × 34914 × (3/20)
= 34914/20
= 1745.70
Total interest for 2 years 4 months = 8514 + 1745.70
= 10259.70
Total amount for 2 years 4 months = 26400 + 10259.70
= ₹ 36659.70
<h3>
So , the correct answer is ₹ 36659.70 . </h3>
Answer:9/16
Step-by-step explanation:
Since we know it's 3/4 use
r=(3/4)² .... 
=
Answer: 8.6:8.6
Explanation:
1:n is the form you want.
n is 8.6. change the n value so it is 1:8.6
1 is 1 times bigger than 8.6
8.6 times 1 is 8.6
so you've got 8.6:8.6
your welcome, i hope this helps
Answer:
(x^2 + 3)(x + 1).
Step-by-step explanation:
x^3 + x^2 + 3x + 3
= x^2(x + 1) + 3(x + 1)
= (x^2 + 3)(x + 1).
Answer: ∠ABE=20°
Step-by-step explanation:
∵ AB=BC
∴ ΔABC is a isosceles triangle
∵ ∠A=30
∴ ∠C=30
∵ The interior angle sum of triangle is 180°
∵ ∠A+∠B+∠C=180
30+∠B+30=180
∠B+60=180
∠B=120 (∠ABC)
∵ ∠EBD+∠ABE+∠ABC=linear pair
∴∠EBD+∠ABE+∠ABC=180°
4x+2x+120=180
6x+120=180
6x=60
x=10
∠ABE=2x=2(10)=20°
Hope this helps!! :)
Please let me know if you have any question
