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blsea [12.9K]
3 years ago
15

How far above the earth's surface will the acceleration of gravity be half what it is at the surface?

Physics
1 answer:
Volgvan3 years ago
4 0
<span>The earth's gravitational pull would be halved when the distance above the earth would equal the radius of the earth. In this case, from the Earth's crust to the core is 1,64. If we want to half the gravitational pull on the Earth, we must consider the equation for gravitational acceleration: g = GM/r^2. G is the gravitational constant of the Earth, and the mass of the Earth. r is the radius of the earth. If g is to be halved, r^2 must be doubled. Therefore, one can use the square root of 2 to multiply the left side of the original equation. If the distance from the Earth's surface to its core is originally 6,378 km, we multiply it by .141414 (square root of 2) to come to 9,020 km. Subtract the original radius, and one comes to 2,642km. So 2,642 km above the Earth, the gravitational acceleration is halved of what it is on the surface.</span>
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A level of
Wittaler [7]

Answer:

x = 2 meters.

Explanation:

Let the position (distance) of fulcrum to the load be x.

Given the following data;

Load = 40 kg

Effort (force) = 40 Newton

Effort arm = 4 - x

To find the position of the fulcrum, we would use the expression;

Effort * effort arm = load * load arm

40 * (4 - x) = 40 * x

160 - 40x = 40x

160 = 40x + 40x

160 = 80x

x = 160/80

x = 2 meters

Therefore, the position (distance) of fulcrum to the load is 2 meters.

7 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
Rudiy27

The tension in the cable is equal to 323.5 N.

<h3>What is the tension in the cable?</h3>

The tension, T in the cable is determined by taking moments about the pivot  marked X.

The angles of the boom and the cable with the horizontal are first calculated.

Angle of the boom with horizontal, θ = tan⁻¹(5/10) = 26.56°

The angle of cable with horizontal, B = tan⁻¹(4/10) = 21.80

Taking moments about the pivot:

175.5 * cos 26.56 + 94.7 * cos 26.56 * 0.5 = T (sin(26.56 + 21.80) * 1

Tension = 241.68/0.747

Tension = 323.5 N

In conclusion, the tension in the cable helps to suspend the crate.

Learn more about tension at: brainly.com/question/24994188

#SPJ1

6 0
2 years ago
What was the hiker's total displacement?<br>A.24 km  B.4 km north  C.14 km northeast  D.0 km
kipiarov [429]
We can see it as two movements: one on the north-south axis and one on the west-east axis.

On the north-south Axis, the hiker went 8 km north and 4 km south, so in total the hiker went 4 km north (we can subtract one for the other and the direction remains that which was bigger)

On the west-easth Axis, the hiker went 6 km east and 6 km west, so in total the hiker  didn't move on this axis! or, he/she moved but then "came back"

So in total, the hiker only moved4 km north - answer B.

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7 0
3 years ago
Read 2 more answers
That
Harrizon [31]
Hey can you please help me?
6 0
3 years ago
The fact that light travels at 300,000 km/s is a consequence of
Tresset [83]
<span>The fact that light travels at 300,000 km/s is a consequence of Energy Conservation
The particle that move with that kind of speed creates energy way faster than the particle that don't. Which means that it would require less effort to produce the energy,</span>
6 0
4 years ago
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