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Svet_ta [14]
3 years ago
7

A level of

Physics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

x = 2 meters.

Explanation:

Let the position (distance) of fulcrum to the load be x.

Given the following data;

Load = 40 kg

Effort (force) = 40 Newton

Effort arm = 4 - x

To find the position of the fulcrum, we would use the expression;

Effort * effort arm = load * load arm

40 * (4 - x) = 40 * x

160 - 40x = 40x

160 = 40x + 40x

160 = 80x

x = 160/80

x = 2 meters

Therefore, the position (distance) of fulcrum to the load is 2 meters.

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A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with
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Answer:

mass of second ball is 0.84 kg

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mass of the second ball

solution

we know here elastic head on collision and

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we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

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we know 2nd ball was on rest so v2 = 0

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solve and we get

m2 = 3m1

m2 = 3( 0.280) = 0.84

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