Always convert to moles when comparing compounds.
Molar mass of a compound is the sum of it's atomic molar mass units.
Mg = 24.3 g/mol Mg
O2 = 16 + 16 = 32 g/mol O2
MgO = 24.3 + 16 = 40.3 g/mol MgO
Determine the moles of each reactant/product.
2.2 g Mg * (1 mol/24.3 g Mg) = 0.09 mol Mg
3.6 O2 * (1 mol/32 g O2) = 0.1125 mol O2
2.7 g MgO * (1 mol/40.3 g MgO) = 0.067 mol MgO
Check if there's a limiting reagent. For every 1 O2 we need 2 Mg
0.1125 mol O2 * 2 = 0.225 mol Mg needed.
So Mg is a limiting reagent. We have plenty of O2 which is typically the case when oxygen is a reactant.
Figure out how much product should form based on the moles of limiting reagent. For every 2 Mg 2 MgO are formed. So it's a 1:1 ratio.
0.09 mol Mg ---> 0.09 mol MgO
compare the expected 0.09 mol MgO to the actual 0.067 mol MgO obtained. Calculate the percent obtained.
(0.067 mol MgO obtained) / (0.09 mol MgO expected) * 100 = 74.44 % yield
Answer:
Explanation:
Temperatur is proportional to volume so when temperature drops so does volume
Based on the information on the student looking for an element that will bond with sodium, the element that will likely bond with sodium is bromine.
<h3>How do elements bond?</h3>
Elements bond with one another in a chemical manner to form compounds, which cannot be broken down into their constituent elements without being destroyed.
According to this question, a student is looking for an element that will bond with sodium (Na) with the knowledge that table salt is a compound of sodium and chlorine (Cl).
This suggests that an element that will likely bond with sodium must be in the same group with chlorine because they will possess the same chemical properties.
Therefore, based on this information, the element that will likely bond with sodium is bromine.
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