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BabaBlast [244]
3 years ago
11

A team of engineers is doing a cost-benefit analysis to determine whether

Chemistry
1 answer:
beks73 [17]3 years ago
3 0

Answer:

1) The risk of high cost due to increased resource requirements

2) The risk of late entry into the (a changed) market

Explanation:

The analysis being performed by the engineers = A cost benefit analysis to determine if a new technology should be developed

A cost-benefit analysis is a process of appraising or measuring the advantages, benefits of a policy, action or decision, so as to find the (equilibrium) balance point between the costs of the decision or action

The risk to be considered are;

1) The risk of high cost due to increased resource requirements

The increased cost required for the development of the new technology now which due to the unlikely existence of a similar invention in the market that will give them an advantage of increased profits

2) The risk of late entry into the (a changed) market

The changes in the consumer preferences, market landscape, and the likely introduction into the market of a similar invention by the competition in the near future which will reduce the amount of profits that can be gained from the invention

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4.7e^6 is how I would write it. You simply count in from the right side where the decimal is until you reach the point just before the 4.
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Primary alcohol oxidation products
Yuliya22 [10]

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write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.

The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.

This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.

Oxidizing the different types of alcohols

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3 0
3 years ago
Determine the number of atoms in 41.0 grams of calcium, Ca. (The mass of one mole of calcium is 40.08 g.)
Dovator [93]

Hi there!

Let me know if you have questions about my answer:

6.15 × 10²⁴

Explanation:

To find the number of atoms, divide the mass of calcium (m) by its molar mass (MM). This will give you the number of moles of calcium (n).

n = m/MM            Start with a formula

=\frac{41.0g}{40.08g/mol}             Substitute values from the question

= \frac{41.0g*1mol}{40.08g}             Simplify

= \frac{41.0mol}{40.08}                 Cancel out the units "g"

= 1.022...mol          Number of moles of calcium, with 4 significant figures

Then, multiply the number of moles of calcium (n) by Avogadro's number (N_{A}) to find the number of calcium atoms.

Number.of.Ca=n*N_{A}      Start with a formula

= 1.022mol*\frac{6.022*10^{23}Ca}{1mol}      Substitute values from the question

= \frac{1.022mol*6.022*10^{23}Ca}{1mol}           Simplify

= 1.022*(6.022*10^{23}Ca)     Cancel out the units "mol"

= 6.154*10^{24} Ca                   Multiply, leave one extra digit to help round. "4" tells you to round down.

= 6.15*10^{24} Ca                     Final answer to 3 significant figures*

*When multiplying and dividing numbers, your final answer will have the same number of significant figures as the number with the least number of significant figures in the question.

40.08 has 4 significant figures. 41.0 has 3 significant figures. So, you want 3 significant figures in your final answer.

I hope this helps!

Learn more about Avogadro's number here:

brainly.com/question/1445383

Check out another answer that uses significant figures:

brainly.com/question/3721164

7 0
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Note: Hope this helps, and I hope this is want it was asking. Good luck :)

8 0
3 years ago
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