Answer:
Total worth of gold in the ocean = $5,840,000,000,000,000
Explanation:
As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.
Therefore, In 1 L of ocean water there will be,
(4.0 x 10^-10)/0.0021
= 1.9045 x 10^-7 g of gold per Liter of ocean water.
So in 1.5 x 10^-21 L of ocean water, there will be
(1.9045 x 10^-7) * (1.5 x 10^-21)
= 2.857 x 10^14 g of gold in the ocean.
1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is
20.44 * (2.857 x 10^14)
= $5,840,000,000,000,000
A.a low basket with plastic liner
The sand provides a rough surface on top of the ice for the cars' tires to grip onto. It provides more friction. Salt melts the ice and often provides more friction (the disadvantage is that it eats concrete!).
Because water is polar and oil is nonpolar, their molecules are not
attracted to each other. The molecules of a polar solvent like water are
attracted to other polar molecules, such as those of sugar. This explains
why sugar has such a high solubility in water. Ionic compounds, such
as sodium chloride, are also highly soluble in water. Because water
molecules are polar, they interact with the sodium and chloride ions.
In general, polar solvents dissolve polar solutes, and nonpolar solvents
dissolve nonpolar solutes. This concept is often expressed as “Like
dissolves like.”
So many substances dissolve in water that it is sometimes called
the universal solvent. Water is considered to be essential for life
because it can carry just about anything the body needs to take in
or needs to get rid of.
Sulfuric acid is considered as a Bronsted acid because it is a proton donor. When in solution, the molecules of the compound dissociates into ions, the hydrogen ion and the the sulfate ion. It donates the hydrogen ion so it is an acid, a bronsted acid.
