Answer:
![[H^+]=1.78x10^{-8}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.78x10%5E%7B-8%7DM)
Explanation:
Hello there!
In this case, according to the given information about the pH, it is firstly necessary for us to remember that the pH is defined as the potential of the hydrogen ions in the solution and the concentration of those ions represents how many of them are present in the solution; in such a way, it is possible for us use:
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
Whereas the concentration of hydrogen ions can be calculated as follows:
![[H^+]=10^{-pH}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-pH%7D)
So we plug in the given pH to obtain:
![[H^+]=10^{-7.75}=1.78x10^{-8}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-7.75%7D%3D1.78x10%5E%7B-8%7DM)
Regards!
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