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Dominik [7]
2 years ago
13

Compound B, C6H12O2, was found to be optically active, and it was oxidized to an optically active carboxylic acid A, by Ag (aka,

Tollens Reagent). Oxidation of B by PCC gave an optically inactive compound X that reacted with Zn amalgam/HCl to give 3-methylpentane. With Na2Cr2O7/H2SO4, compound B was oxidized to an optically inactive dicarboxylic acid C, C6H10O4. Provide the structures of A, B, and C (ignore specific configuration of any stereocenters).

Chemistry
1 answer:
Daniel [21]2 years ago
8 0

Answer:

Check the explanation

Explanation:

Acidipic Acid <u><em>(which is an essential dicarboxylic acid for manufacturing purposes with about 2. 5 billion kilograms produced per year. It is mainly used for the production of nylon and its related materials.)</em></u>

Going by the question, since the H_{2}  CrO_{4} is comparatively mild oxidizing agent than the CrO_{3}, it only oxidizes the carbon group

Kindly check the attached image below for the full explanation to the question above.

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Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

<h3>What is electroplating?</h3>

Electroplating is a way of electrolysis, where a thin layer of metal is used to plate a determined object. It is a kinda process to purify a material you want.

The anode contains the metal you want to plate with, in this case, the Ag.

The anode contains the half-reaction of oxidation so:

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In the cathode, you have the spoon, which it takes place the half-reaction of reduction:

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The electrolytic cell, where the redox reaction takes place, must be filled with a AgNO₃ solution.

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

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