To
determine the volume of both concentration of the solution to make another concentration of solution, we need to set up
two equations since we have two unknowns. <span>
For the first equation, we do a mass balance:
mass of 50% solution + mass of 20% solution =
mass of 40% solution
M1 + M2 = M3
For the second equation, we do a component balance,</span>
<span>
M1(50%) + M2(20%) = M3(40%)
.50M1 + .20M2 = .40M3
To determine the ratio, we assume we have to make a 100 g of the 40% solution. So, the equation would change to</span>
<span>
</span>
<span>M1 + M2 = 100</span>
.50M1 + .20M2 = (100)(.40) = 40
Solving for M1 and M2,
M1 = 66.67 g
M2 = 33.33 g
So, the ratio of the 20% and the 50% would be approximately 33.33/66.67 = 0.5.
Answer:
Covalent molecule
Explanation:
i just had got the answer right
Answer: D. The number of molecules having Er or greater doubles.
Explanation: As the temperature increases from 20°C to 30°C, the number of molecules with maximum energy decreases, but the number of effective collisions which result into the formation of product doubles.
This is due to doubling of molecules which possess energy equal to or greater than
which means now double number of molecules will be able to cross the energy barrier and hence the formation of product increases and hence the rate increases to double.
Answer: (1). If calcium bromide is dissolved in water you can say that the equilibrium concentrations of calcium and bromide ions are high.
(2). The solubility of calcium bromide in water is high.
Explanation:
We know that for a reaction its solubility product is equal to the product of concentration of ions present.
For example, 
![K_{sp} = [Ca^{2+}][Br^{-}]^{2}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BBr%5E%7B-%7D%5D%5E%7B2%7D)
As it is given that for this reaction
> 1. Hence, the product of concentration of both these ions will be greater than 1 which means that products are favored.
Therefore, equilibrium concentrations of calcium and bromide ions are high.
Also, more is the number of these ions formed more will be the solubility of the compound (
).
As a result, the solubility of calcium bromide in water is high.