Answer:
HCl(aq) + KOH(aq) ===> H2O(l) + KCl(aq)
Note the stoichiometry of the balanced equations shows us that HCl and KOH react in a 1:1 mole ratio. So, let us find moles of HCl and moles of KOH that are present:
moles HCl = 250.0 ml x 1 L/1000 ml x 0.25 mol/L = 0.06250 moles HCl
moles KOH = 200.0 ml x 1 L/1000 ml x 0.40 mol/L = 0.0800 moles KOH
You can see that there are more moles of KOH than there are of HCl, meaning that KOH is in excess and after neutralizing all of the HCl, the solution will be left with excess KOH making the pH > 7 = BASIC
Answer:
Volume of the cube is 2*2*2 = 8cm^3.
Divide the weight (40g) over the volume (8cm^3).
Density is 5g/cm^3. Definitely not gold.
Explanation:
Answer:
linear
Explanation:
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Answer:MORE THAN 50 STUDIES WERE CONDUCTED
THE US PUBLIC HEALTH SERVICE WAS RESPONSIBLE FOR PART OF THE STUDY
Explanation: Just completed the assignment Egenuity , i hope this helps .
