Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Geometry</u>
- Area of a Rectangle: A = lw
<u>Algebra I</u>
- Exponential Property:

<u>Calculus</u>
Derivatives
Differentiating with respect to time
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Explanation:
<u>Step 1: Define</u>
Area is A = lw
2w = l
w = 300 m

<u>Step 2: Rewrite Equation</u>
- Substitute in <em>l</em>: A = (2w)w
- Multiply: A = 2w²
<u>Step 3: Differentiate</u>
<em>Differentiate the new area formula with respect to time.</em>
- Differentiate [Basic Power Rule]:

- Simplify:

<u>Step 4: Find Rate</u>
<em>Use defined variables</em>
- Substitute:

- Multiply:

- Multiply:

Answer:
cus on a specific area of your living space
Explanation:
More force needs to be applied
Answer:
- the Magnetic field lines will spread out of the north end of the magnet.
- the magnetic fields will three-dimensional and resemble a bubble.
Explanation:
- Usually, when drawing magnetic field lines, we start outwardly from the North pole to the South Pole. This same direction is also prevalent on the Earth due to the fact that the Earth functions as a giant magnet. Thus, one characteristic of the model is that the Magnetic field lines will spread out of the north end of the magnet.
- Another thing is that Magnetic field forces are usually driven as a result bubble like configuration which affects the objects that are in such a configuration. Thus, another characteristic of the model is that the magnetic fields will three-dimensional and resemble a bubble.
When analyzing inelastic collisions, we need to consider the law of conservation of momentum, which states that the total momentum, p, of the closed system is a constant. In the case of inelastic collisions, the momentum of the combined mass after the collision is equal to the sum of the momentum of each of the initial masses.
p1+p2+...=pf
In our case we only have two masses, which makes our problem fairly simple. Lets plug in the formula for momentum; p=mv.
m1v1+m2v2=(m1+m2)vf
To find the velocity of the combined mass we simply rearrange the terms.
vf=m1v1+m2v2m1+m2
Plug in the values given in the problem.
vf=(3.0kg)(1.4m/s)+(2.0kg)(0m/s)03.0kg+2.0kg
vf=.84m/s