The answer is the following:
Water vapor in the air cools and forms clouds.
Answer: Alex traveled a distance of 27.0 km in 2.25 hours.
Further Explanation:
Speed is how fast an object moves or how far an object travels per unit time. If the distance traveled and the total time of travel are known, the speed can be calculated using the formula:
In the problem, we are given:
speed = 12.0 km/hr
time = 2.25 hr
We are looking for the distance traveled by Alex which can be represented by the variable d.
We can solve for d by manipulating the speed formula to get the equation:
distance, d \ = \ (speed)(time)[/tex]
Plugging in our values for speed and time, we get the equation:
Since the number of significant figures of the given is 3, the answer must be expressed with 3 significant figures, too.
Thus, the distance Alex traveled for 2.25 hours at a speed of 12.0 km/hr is 27.0 km.
Learn More
- Learn more about Velocity brainly.com/question/862972
- Learn more about Acceleration brainly.com/question/4134594
- Learn more about Distance - Time Graphs brainly.com/question/1378025
Keywords: speed, distance, kinematics
Answer:
Not all the pictures are popping up. So I can't answer them all. :(
Explanation:
The fist one is B. And the second is D. That's all I can see. I hope this helps a little bit :(
Answer:
Bi. Current in 15.4 Ω (R₁) is 7.14 A.
Bii. Current in 21.9 Ω (R₂) is 5.02 A.
Biii. Current in 11.7 Ω (R₃) is 9.40 A.
C. Total current in the circuit is 21.56 A.
Explanation:
Bi. Determination of the current in 15.4 Ω (R₁)
Voltage (V) = 110 V
Resistance (R₁) = 15.4 Ω
Current (I₁) =?
V = I₁R₁
110 = I₁ × 15.4
Divide both side by 15.4
I₁ = 110 / 15.4
I₁ = 7.14 A
Therefore, the current in 15.4 Ω (R₁) is 7.14 A.
Bii. Determination of the current in 21.9 Ω (R₂)
Voltage (V) = 110 V
Resistance (R₂) = 21.9 Ω
Current (I₂) =?
V = I₂R₂
110 = I₂ × 21.9
Divide both side by 21.9
I₂ = 110 / 21.9
I₂ = 5.02 A
Therefore, the current in 21.9 Ω (R₂) is 5.02 A
Biii. Determination of the current in 11.7 Ω (R₃)
Voltage (V) = 110 V
Resistance (R₃) = 11.7 Ω
Current (I₃) =?
V = I₃R₃
110 = I₃ × 11.7
Divide both side by 11.7
I₃ = 110 / 11.7
I₃ = 9.40 A
Therefore, the current in 11.7 Ω (R₃) is 9.40 A.
C. Determination of the total current.
Current 1 (I₁) = 7.14 A
Current 2 (I₂) = 5.02 A
Current 3 (I₃) = 9.40 A
Total current (Iₜ) =?
Iₜ = I₁ + I₂ + I₃
Iₜ = 7.14 + 5.02 + 9.40
Iₜ = 21.56 A
Therefore, the total current in the circuit is 21.56 A
Answer:
D. 90
Explanation:
because even if there is a shadow of doubt the person should not be persecuted as it could lead to false imprisonment
