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scoundrel [369]
3 years ago
13

Light traveling through air encounter a second medium which slows the light to 2.7 x 10^8. What is the index of the medium?

Physics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

1.11

Explanation:

The index of the medium can be calculated using below formula

V= c/ n ............eqn(1)

Where V= velocity of the light is reduced to while traveling through the second medium= 2.7 x 10^8 m/s

n= index of the medium

c= speed of light= 3 x 10^8 m/s

Substitute for the values in eqn(1)

2.7 x 10^8 = (3 x 10^8 m/s)/ n

Making " n" subject of the formula, we have

n= (3 x 10^8 )/(2.7 x 10^8)

n= 1.11

Hence, the index of the medium is 1.11

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Alex rides her bike at 12.0 km/hr for 2.25 hr. what distance has alex traveled?
Ymorist [56]

Answer: Alex traveled a distance of 27.0 km in 2.25 hours.  

Further Explanation:

Speed is how fast an object moves or how far an object travels per unit time. If the distance traveled and the total time of travel are known, the speed can be calculated using the formula:

speed \ = \frac{distance}{time}

In the problem, we are given:

speed = 12.0 km/hr

time = 2.25 hr

We are looking for the distance traveled by Alex which can be represented by the variable d.

We can solve for d by manipulating the speed formula to get the equation:

distance, d \ = \ (speed)(time)[/tex]

Plugging in our values for speed and time, we get the equation:

distance \ = \ (12.0 \ \frac{km}{hr})(2.25 \ hr)\\ \boxed {distance,d\ = \ 27.0 \ km}

Since the number of significant figures of the given is 3, the answer must be expressed with 3 significant figures, too.

Thus, the distance Alex traveled for 2.25 hours at a speed of 12.0 km/hr is 27.0 km.

Learn More

  1. Learn more about Velocity brainly.com/question/862972
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Keywords: speed, distance, kinematics

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Integrated Science- Study Guide: Water
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Answer:

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Explanation:

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3 years ago
Problem 31:
blagie [28]

Answer:

Bi. Current in 15.4 Ω (R₁) is 7.14 A.

Bii. Current in 21.9 Ω (R₂) is 5.02 A.

Biii. Current in 11.7 Ω (R₃) is 9.40 A.

C. Total current in the circuit is 21.56 A.

Explanation:

Bi. Determination of the current in 15.4 Ω (R₁)

Voltage (V) = 110 V

Resistance (R₁) = 15.4 Ω

Current (I₁) =?

V = I₁R₁

110 = I₁ × 15.4

Divide both side by 15.4

I₁ = 110 / 15.4

I₁ = 7.14 A

Therefore, the current in 15.4 Ω (R₁) is 7.14 A.

Bii. Determination of the current in 21.9 Ω (R₂)

Voltage (V) = 110 V

Resistance (R₂) = 21.9 Ω

Current (I₂) =?

V = I₂R₂

110 = I₂ × 21.9

Divide both side by 21.9

I₂ = 110 / 21.9

I₂ = 5.02 A

Therefore, the current in 21.9 Ω (R₂) is 5.02 A

Biii. Determination of the current in 11.7 Ω (R₃)

Voltage (V) = 110 V

Resistance (R₃) = 11.7 Ω

Current (I₃) =?

V = I₃R₃

110 = I₃ × 11.7

Divide both side by 11.7

I₃ = 110 / 11.7

I₃ = 9.40 A

Therefore, the current in 11.7 Ω (R₃) is 9.40 A.

C. Determination of the total current.

Current 1 (I₁) = 7.14 A

Current 2 (I₂) = 5.02 A

Current 3 (I₃) = 9.40 A

Total current (Iₜ) =?

Iₜ = I₁ + I₂ + I₃

Iₜ = 7.14 + 5.02 + 9.40

Iₜ = 21.56 A

Therefore, the total current in the circuit is 21.56 A

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