Let's plug the values and see which couple satisfy the equation: since
, if we plug the values from the first option
we have
![6 = 2\cdot 3^1 = 2\cdot 3](https://tex.z-dn.net/?f=%206%20%3D%202%5Ccdot%203%5E1%20%3D%202%5Ccdot%203%20)
which is correct.
If we plug the values from the second option
we have
![9 = 2\cdot 3^1 = 2\cdot 3](https://tex.z-dn.net/?f=%209%20%3D%202%5Ccdot%203%5E1%20%3D%202%5Ccdot%203%20)
which is not correct
If we plug the values from the third option
we have
![9 = 2\cdot 3^2= 2\cdot 9](https://tex.z-dn.net/?f=%209%20%3D%202%5Ccdot%203%5E2%3D%202%5Ccdot%209%20)
which is not correct
If we plug the values from the fourth option
we have
![12 = 2\cdot 3^2= 2\cdot 9](https://tex.z-dn.net/?f=%2012%20%3D%202%5Ccdot%203%5E2%3D%202%5Ccdot%209%20)
which is not correct
So, the answer is the first one.
Answer: The first one
Step-by-step explanation:
-6c + 11d = 20
-6c + 11d = 20
They're the same equation meaning they'll be on the same line. They would have infinite solutions.
Answer:
Step-by-step explanation:
Given that ![r = 0.952](https://tex.z-dn.net/?f=r%20%3D%200.952)
We have coefficient of determination
![r^2 =0.952^2\\=0.906304](https://tex.z-dn.net/?f=r%5E2%20%3D0.952%5E2%5C%5C%3D0.906304)
=90.63%
This implies that nearly 91% of variation in change in dependent variable is due to the change in x.
The coefficient of determination is the square of the correlation (r) between predicted y scores and actual y scores; thus, it ranges from 0 to 1.
An R2 of 0 means that the dependent variable cannot be predicted from the independent variable.
An R2 of 1 means the dependent variable can be predicted without error from the independent variable.
Answer:
Step-by-step explanation:
i dont think thats possible without the y value