18ft•12inches= 216 inches
15ft•12inches=180inches
If both are sold for 1$ per inch then the plumber spent $396.
You are to subtract the functions to get a new function h(x)
h(x) = f(x) - g(x)
replace function name with the equivalent expression.
h(x) = 2(1.2)x - (2x + 1.4)
Distribute the negative sign to the second function - g(x)
h(x) = 2(1.2)x - 2x - 1.4
Now compare to the possible solutions... It appears the next step is to factor 2 out of 1.4 to get 0.7. (all possible solutions end with 0.7)
h(x) = 2(1.2)x + 2( -x - 0.7)
now factor 2 out of all terms
h(x) = 2(1.2x - x - 0.7)
Answer D.
Answer:
The liters that the tank will contain at 5:11 PM that day are:
Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
- 19,140 L - 8,097 L = 11,043 L
And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
- Outlet flow =
- Outlet flow =
- Outlet flow = 613.5
Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
- Outlet flow =
- Volume = Outlet flow * time
And replace the values to obtain the new volume pumped:
- Volume = 613.5 * 6 min
- Volume = 3681 L.
At last, you must subtract these liters from the last volume identified in the tank:
- New Volume in the tank = 8097 L - 3681 L
- New Volume in the tank = 4416 L
The volume in the tank at 5:11 PM is <u>4416 Liters</u>.
We know that a rectangle is dilated by a factor of 1/5 which means that the area of a rectangle is dilated by a factor of 1/25. I get 1/25 because each side was dilated by a factor of 1/5, so I just need to take 1/5×1/5=1/25 as the factor of area if rectangle.
Then, the new rectangle is 4 square yards, so we just need to find the area of the old or pre-rectangle. Furthermore, we know that the pre-rectangle is 25 times bigger than the new rectangle based on what we did above, so the area of the pre-rectangle is:
4×25=100 square yards.
However, the question asked us to find the possibility dimension of the original images.
Area of the rectangle=
length× width
100 square yards
length=20 yards, width=5 yards
length=100 yards, width=1 yard
length=25 yards, width=4 yards. Hope it help!
