NEED HELP WHATS THE ANSWERS FOR THESE 2

Mathematics

1 answer:

Maurinko [17]3 years ago

7 0

I believe the first on is -1 and the second one is NO SOLUTION

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Can somebody please help with these two questions?

Nitella [24]

Answer:

#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19

Step-by-step explanation:

You can solve using the quadratic equation or by solving with the perfect square

$\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}$ = $x^{2}+5x-2=0\\ \frac{-5+/-\sqrt{5^{2}-4(1)(-2) }}{2(1)}$

x is approximately 0.37, -5.37

6 0

3 years ago

Find the vertex of an angle of an isosceles triangle if one base angle is 8 less than half the vertex?

skad [1K]

Vertex angle = x
1 base angle = 1/2x - 8

180-x = (1/2x-8)x2
180-x = x-16
196-x = x
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x=98

If you want explanation please ask me .

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3 years ago

Which equation represents the circle described?

bazaltina [42]

We have the equation:

$x^2+y^2-8x-6y+24=0$

By arranging this equation in terms of x and y, we have:

$x^2-8x+y^2-6y=-24 \\ \\$

By using the method of completing the square, we have:

$x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}$