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4 years ago

The amount of disorder in a system is measured by it's:

1 answer:

3 0

The amount or disorder in a chemical system or system is measured by it's Entropy. Entropy is the simply the measure of the amount of disorder or lack of structure present within a system.

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The term Reuther Ford gave to the positively charged particles in the nucleus of an antom was

lubasha [3.4K]

The term Rutherford gave to the positively charged particles in the nucleus of an atom was/is Proton.

Hope this helps!

4 0

4 years ago

A baker is decorating cupcakes using 3 cherries for every 1 cupcake. If the baker has 12 cherries and 5 cupcakes, what is the th

11111nata11111 [884]

C. 4 decorated cupcakes.

Because 12 divided by 3 = 4, so you can have 4 cupcakes each with 3 cherries

7 0

3 years ago

Read 2 more answers

The average molecular weight for element X is 59.97 g/mol. There are two known isotopes of element X, one weighing 59 g/mol, and

Temka [501]

Answer:

The correct answer is:48.5% X-59, 51.5% X-61

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of X-59 isotope be 'x'. So, fractional abundance of X-61 isotope will be '1 - x'

For X-59 isotope:

Mass of X-59 isotope =59 g/mol

Fractional abundance of X-59 isotope = x

For X-61 isotope:

Mass of X-61 isotope = 61 g/mol

Fractional abundance of X-61 isotope = 1 - x

Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

$59.97 g/mol=[(59 g/mol\times x)+(61 g/mol\times (1-x))]\\\\x=0.515$

Percentage abundance of X-59 isotope = $0.515\times 100=51.5\%$

Percentage abundance of X-61 isotope = $(1-0.515)=0.485\times 100=48.5\%$

Hence, the percentage abundance of both the isotopes X-59and X-61 are 51.5% and 48.5% respectively.

4 0

3 years ago

To determine the molecular weights of the acid, a student dissolved a pure sample (400.0 mg) in a water to a total volume of 100

klasskru [66]

Answer:

83.86g/mol is the molecular weight of the acid

Explanation:

Molecular weight is the ratio of mass in grams and moles present. That means we need to determine the mass in grams (400.0mg = 0.400g) and the moles of the acid that can be detemined by using its reaction with NaOH:

<em>Moles acid:</em>

First, we need to assume the acid is a monoprotic acid (Only 1 proton is acid and reacts with a base).

when the acid, HX, reacts with NaOH there is produced:

HX + NaOH → H₂O + NaX

<em>Where 1 mole of HX reacts per mole of NaOH. That means the moles at the endpoint of NaOH = Moles of HX:</em>

<em />

Moles NaOH:

15.90mL= 0.01590L * (0.0750mol / L) = 1.193x10⁻³ moles of NaOH = Moles of HX are present.

The acidic solution was diluted to 100.0mL but only 25.00mL were taken, that is:

25.00mL / 100.00mL = 1/4 of the acid was titrated.

And moles of HX in the original solution are:

1.193x10⁻³ moles of HX * 4 = 4.77x10⁻³ moles of HX

<em>It is multiplied by 4 because the real amount of acid is 4 times the titrated amount.</em>

<em />

Thus, molecular weight is:

0.4000g / 4.77x10⁻³ moles of HX =

<h3>83.86g/mol is the molecular weight of the acid</h3>

8 0

3 years ago

What did Aristotle believe?

Crank

Answer:

C.) That all matter was composed of earth, fire, water and air

Explanation:

Just took the test

4 0

3 years ago