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docker41 [41]
3 years ago
5

A 1.167 grams sample of hydrated Nickel (II) Chloride is heated until a constant mass is achieved. The constant mass of the samp

le is .750 grams. What is the formula and name of the hydrate?
Chemistry
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

NiCl₂·4H₂O, its name being nickel (II) chloride tetrahydrate.

Explanation:

The constant mass achieved after heating is the mass of anhydrous nickel (II) chloride, NiCl₂. While the mass lost was water.

  • Mass lost = 1.167 g - 0.750 g = 0.417 g

Now we <u>convert 0.750 g of NiCl₂ into moles</u>, using <em>its molar mass</em>:

  • 0.750 g NiCl₂ ÷ 129.6 g/mol = 0.0058 mol NiCl₂

Then we <u>convert 0.417 g of H₂O into moles</u>:

  • 0.417 g H₂O ÷ 18 g/mol = 0.0231 mol H₂O

With the above information we can calculate that the number of H₂O moles is 4 times higher than the number of NiCl₂ moles.

Meaning that <em>the formula of the hydrate is NiCl₂·4H₂O</em>, its name being nickel (II) chloride tetrahydrate.

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Answer:

\large \boxed{\text{0.0038 mol/L}}

Explanation:

1. Calculate the initial moles of acid and base

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C/mol:    -0.00500   -0.005 00

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We have an excess of 0.0003 mol of base.

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\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}

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