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Rzqust [24]
3 years ago
9

A database search would be the best method of gathering which type of data? data?

Chemistry
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

I think ans is a or b

Explanation:

hope it is help full

<h3>Mark me a brainlist</h3>
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Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con
Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is K_a\times K_b

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)

K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}

b) PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)

K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}

For overall reaction on adding a and b we get c

c) P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)

K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}

K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}

The equilibrium constant for the overall reaction is K_a\times K_b

4 0
3 years ago
Write half reactions and the overall reaction occurred during discharging of acid lead battery.
Gre4nikov [31]
When  battery  discharge / delivering  current  the  lead  at  the  anode  is  oxidized
that  is ;
pb---->pb+  2e-
since  the  lead  ions  are  in  presence  of  aquous   sulfate  in  insoluble  lead  sulfate  precipitate onto the  electrode
the  overall   reaction  at  the  anode  is  therefore
Pb +  SO4^2-  ---> PbSO4  +  2e-
5 0
3 years ago
Formula for Hydrocloric Acid.
Elden [556K]
HCl is the formula for hydrocloric acid
6 0
3 years ago
What are some chemical changes in oxygen?
Zinaida [17]

the oxidation reaction between oxygen and sodium produces sodium oxide. In many cases, an element may form more than one oxide.

Explanation:

4 0
3 years ago
g What is the molarity of hydrochloric acid if 40.95 mL of HCl is required to neutralize 0.550 g of sodium oxalate, Na2C2O4
kykrilka [37]

Answer:

0.0002 M

Explanation:

<em>The molarity of the HCl required would be 0.0002 M.</em>

First, let us consider the balanced equation of the reaction:

Na_2C_2O_4 + 2HCl = 2NaCl + H_2 + 2CO_2

<em>Stoichiometrically, 1 mole of </em>Na_2C_2O_4<em> reacts with 2 moles of </em>HCl<em> for a complete neutralization reaction.</em>

Recall that: mole = \frac{mass}{molar mass}

Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole

<em>If 1 mole </em>Na_2C_2O_4<em> requires 2 moles HCl, then 0.0041 mole will require</em>:

    0.0041 x 2 = 0.0082 mole HCl

Volume of the HCl = 40.95 L

Molarity = mole/volume

Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M

7 0
3 years ago
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