Answer:
Option b. 0.048 M
Explanation:
We have the molecular weight and the mass, from sulcralfate.
Let's convert the mass in g, to moles
1 g . 1 mol / 2087 g = 4.79×10⁻⁴ moles.
Molarity is mol /L
Let's convert the volume of solution in L
10 mL . 1L/1000 mL = 0.01 L
4.79×10⁻⁴ mol / 0.01 L = 0.048 mol/L
Answer:
8×10^(-3) mol/L
Explanation:
The formula for finding the hydrogen ion concentration is...
[H⁺] = 10^-ph
[H⁺] = 10^(-2.1)
[H⁺] = 0.00794...mol/L = 8×10^(-3) mol/L
The answer is to 1 significant digit because the pH has one decimal place.
Answer:
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The name of this specific silicon isotope is Si -18
To make computations easier, let us assume that there is 1 liter solution of the sample.
So using the density formula to know what the mass of this sample would be:
1 L x 1000 mL / 1L x 1.20g/ 1 mL = 1120g
Now use the percent concentration by mass to know how many grams of HCl you can have:
1120 g sol x 39 g HCl / 100 g = 313.6 g HCL
To determine the solution's molarity, use the molar mass to know the number of moles present:
313.6g x 1 mole / 36.46g = 8.60 moles
since the sample has a volume of 1 L, the molarity is:
C = n / V = 8.60 moles / 1.0 L = 8.60 M
To get the solution's molarity, determine the mass of water.
Msol = Mwater + Macid
Mwater = Msol - Macid = 1120 - 313.6 = 806.4 g
The molarity will be:
b = n/ Mwater = 8.60 moles / 806.4 x 10^-3 = 10.66 molal
the solution's molarity will be equal to its normality since HCl acid can only release one mole of protons per mole of acid
Normality = 8.6 N
