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3 years ago

Which methods could be used to dilute a solution of sodium chloride (NaCl)? Select all that apply.

Chemistry

1 answer:

Pavel [41]3 years ago

4 0

Answer:

NaOH₂2CO3

Explanation:yes i know it is not a Balinese equation

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What is the mass of 13 gold atoms?

Ludmilka [50]

Answer:

uuuh 4.25191 × 10-21 grams????

Explanation:

8 0

3 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

How much would a 10 kg suitcase weigh on the surface of…? a. The Moon b. Mars c. Saturn d. Pluto

alukav5142 [94]

Answer:

Is this the full question

Explanation:

Reply or love the message so i can get a notification

8 0

2 years ago

Explain the need of the term avarage atomic mass

vodomira [7]

Answer:

The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotopе). An element does not have an absolute atomic mass.

Hope this helps :)

4 0

3 years ago

For a particular reaction, ΔH=−111.4 kJ/mol and ΔS=−25.0 J/(mol·K).

PtichkaEL [24]

That’s the answer ^^^^

3 0

3 years ago