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3 years ago

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Which term describes the forces acting on the car? A. inertial B. buoyant C. balanced D. unbalanced

1 answer:

Anna35 [415]3 years ago

3 0

The answer is unbalanced because the forces actually act on each other.

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2. A person applies a force of 66 N to a fridge as they push it across the length of a standard tennis court. So far today, the

Lubov Fominskaja [6]

Answer:

$P=39.2205\, watt$

$E=374.948 \,cal$

Explanation:

Given that:

force applied, $F=66\,N$

displacement, $s=23.77\,m$ (length of a tennis court)

time taken for pushing, t = 40 s

Since, work is given by:

$W=F.s$

$W=66\times 23.77$

$W=1568.82\,J$

Now, power is given as:

$P=\frac{W}{t}$

$P=\frac{1568.82}{40}$

$P=39.2205 \,watt$

Calories consumed is:

$E= 1568.82\times 0.239$

$E=374.948\, cal$

3 0

3 years ago

With a mass of 109 kg, Baby Bird is the smallest monoplane ever

OLga [1]

Total resultant velocity=5.11-3.27=1.84m/s

m_1=61.4kg
m_2=109kg
v_1=1.84m/s
v_2=?

$\\ \sf\longmapsto ∆P=P$

$\\ \sf\longmapsto m_1v_1=m_2v_2$

$\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}$

$\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}$

$\\ \sf\longmapsto v_2=112.976/109$

$\\ \sf\longmapsto v_2\approx 1.3m/s$

4 0

2 years ago

The bones of the middle ear cause the to vibrate and change the sound into signals.

olga nikolaevna [1]

If it is a true or false question then it is true

8 0

2 years ago

How does the speed of a sound wave change as the medium through which it traveks changes?

uranmaximum [27]

Increase as density increase and vise versa.
<span>The wavelength increases when a sound wave travels from a less dense to a more dense medium, the speed increases, and the frequency stays the same.</span>

8 0

3 years ago

Two equally charged, 2.098 g spheres are placed with 3.338 cm between their centers. When released, each begins to accelerate at

photoshop1234 [79]

Answer:

$2.64\times 10^{-7} C$

Explanation:

There are two spheres name 1 and 2 and they posses the same charge, which is +q.

And they have equal mass which is 2.098 g.

The distance between these two spheres is, $r=3.338 cm$ .

And the acceleration of each sphere is, $a=269.429 m/s^{2}$ .

Now the coulumbian force experience by 1 sphere due to 2 sphere,

$F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2} }$ .

And also the newton force will occur due to this force,

$F_{21}=ma$ .

Now equate the above two values of force will get,

$\frac{q^{2} }{4\pi\epsilon_{0} r^{2} } =ma$

Further solve this,

$q^{2}=ma4\pi \epsilon_{0} r^{2}$ .

Substitute all the known variables in above equation,

$q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2})$ .

$q=2.64\times 10^{-7} C$ .

6 0

3 years ago