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Cloud [144]
3 years ago
14

6. question is in the picture

Physics
1 answer:
Harlamova29_29 [7]3 years ago
8 0
The answer is c you got to look for answers that make sense
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What’s the kinetic energy of the object? Use .
Fynjy0 [20]

Answer:

18joules

Explanation:

1/2 of 4=2

2 multiply by 9= 18 joules

4 0
3 years ago
The magnitude of the magnetic field that a long and extremely thin current-carrying wire produces at a distance of 3.0 µm from t
Reil [10]

Answer:

Current (I) = 3 x 10^-2 A

Explanation:

As we know, B = 4\pi 10^-7 *l/ 2\pi r

By putting up the values needed from the data...

Current (I) = 2 x 3.14 x (3.0 x 10^-6) (2.0 x 10^-3) / 4 x 3.14 x 10^-7 = 3 x 10^-2 A

6 0
3 years ago
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Corn plants and milkweed plants grow in the same area. Over several years, the milkweed plants have taken over the field and the
erma4kov [3.2K]

Weeds are very important agronomically because they reduce the yield of crops in three ways: by competing with the crop for water, light and nutrients, by interfering with crop harvest, and by contaminating harvested products with weed seeds and toxins. Weeds can reduce yield up to 50% and are responsible for millions of dollars in crop losses each year.

It’s biotic factor would be competition as Competition can be defined as an interaction between organisms or species, in which the fitness of one is lowered by the presence of another.

3 0
3 years ago
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This object is located 13.0 cm to the left of the lens and the image forms at 20.8 cm to the right of the lens.
Alina [70]

Answer:

0.125 cm

Explanation:

1/f = 1/d¡ + 1/d。

Find the focal point

(13.0^-1 + 20.8^-1) = 0.125 m

Focal point = 0.125 m  

6 0
2 years ago
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A geosynchronous satellite moves in a circular orbit around the Earth and completes one circle in the same time T during which t
andreyandreev [35.5K]

Answer:

Explanation:

The time period of geosynchronous satellite must be equal to T .

The radius of its orbit will be (  R+ h )

orbital velocity  V₀ =  \sqrt{\frac{GM}{( R+h)} }

Time period T = 2π( R + h ) / V₀

= 2π( R + h ) x \sqrt{\frac{( R+h)}{GM } }

\frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } = R +h

h = \frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } - R.

7 0
3 years ago
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