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SIZIF [17.4K]
3 years ago
11

Suppose you hear a clap of thunder 14.4 s after seeing the associated lightning strike. The speed of light in air is 3.00 ✕ 108

m/s. (a) How far are you from the lightning strike? (The speed of sound waves in air is 343 m/s.)(b) Do you need to know the value of the speed of light to answer?
Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer

Given,

Time to hear the clap = 14.4 s

speed of the light = 3 x 10⁸ m/s

Speed of sound = 343 m/s

a) distance where lightning strike

    D = s x t

    D = 14.4 x 343

   D = 4939.2 m

b) No, we do not need to know the value of speed of light. Because we need to calculate the distance where we hear the sound. To calculate that we need to know the speed of sound.

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For a proton in the ground state of a 1-dimensional infinite square well, what is the probability of finding the proton in the c
Butoxors [25]

Answer:

The probability of finding the proton at the central 2% of the well is almost exactly 4%

Explanation:

If we solve Schrödinger's equation for the infinite square well, we find that its eigenfunctions are sinusoidal functions, in particular, the ground state is a sinusoidal function for which only half a cycle fits inside the well.

let L be the well's length, the boundary conditions for the wavefunction are:

\psi(0) = \psi(L) =0

And Schrödinger's equation is:  

- \frac{\hbar^2}{2m} \frac{d^2\psi}{dx^2} = E\psi

The solution to this equation are sines and cosines, but the boundary conditions only allow for sine waves. As we pointed out, the ground state is the sine wave with the largest wavelength possible (that is, with the smallest energy).

\psi_0(x)=\sqrt[]{\frac{2}{L} }\, \sin(\frac{\pi x}{L} )\\

here the leading constant is just there to normalise the wavefunction.

Now, if we know the wavefunction, we can know what the probability density function is, it is:

f_X(x) = |\psi|^2

So in our case:

f_X(x) = \frac{2}{L} \sin^2(\frac{\pi x}{L})

And to find the probability of finding the particle in a strip at the centre of the well of width 2% of L we only have to integrate:

P(X \in [0.49 L, 0.51L ])= \int\limits^{0.49L}_{0.51L } {\frac{2}{L} \sin^2(\frac{\pi x}{L})} \, dx

If we do a substitution:

x = u \, L

We get the integral:

\int\limits^{0.49}_{0.51 } 2\,  \sin^2(\pi u)} \, du

This integral can be computed analytically, and it's numerical value is .0399868, that is, almost a 4% probability.

5 0
3 years ago
During a race, a dragster is 200m from the finish line when something goes wrong and it stops accelerating. It travels at a cons
GarryVolchara [31]

Answer:

135 m

Explanation:

Speed = 45 m/s, time = 3 second

The formula for the distance is given by

Distance = speed x time = 45 x 3 = 135 m

4 0
3 years ago
A musical tone sounded on a pi has frequency of 410 Hz and a wavelength of 0.80 m.
spayn [35]
C. I did it bit i forgot how I did it
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3 years ago
What is the acceleration of a softball if it hits the ground with a force 0.50 kg and hits the catchers glove with a force of 25
Rom4ik [11]

Acceleration of the ball is 50 m/s^2

Explanation:

The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the net force

m is the mass

a is the acceleration

For the ball in this problem, we have

m = 0.50 kg (mass)

F = 25 N (force)

thereofre, the acceleration of the ball is

a=\frac{F}{m}=\frac{25}{0.50}=50 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
Light would most likely be transmitted through A. A mirror B. A stone C. A leaf D. A window
ohaa [14]
A window is the most transparent object from these, so that is the answer.
7 0
3 years ago
Read 2 more answers
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