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SIZIF [17.4K]
3 years ago
11

Suppose you hear a clap of thunder 14.4 s after seeing the associated lightning strike. The speed of light in air is 3.00 ✕ 108

m/s. (a) How far are you from the lightning strike? (The speed of sound waves in air is 343 m/s.)(b) Do you need to know the value of the speed of light to answer?
Physics
1 answer:
Marina86 [1]3 years ago
5 0

Answer

Given,

Time to hear the clap = 14.4 s

speed of the light = 3 x 10⁸ m/s

Speed of sound = 343 m/s

a) distance where lightning strike

    D = s x t

    D = 14.4 x 343

   D = 4939.2 m

b) No, we do not need to know the value of speed of light. Because we need to calculate the distance where we hear the sound. To calculate that we need to know the speed of sound.

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The only thing that definitely happens in every such case is:
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2 years ago
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<u>Hello and Good Morning/Afternoon</u>:

<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>

<u>To balance this equation</u>:

⇒ must ensure that there is an equal number of elements on both sides of the equation at all times

<u>Let's start balancing:</u>

  • On the left side of the equation, there are 2 carbon molecule

              ⇒ but only so far one on the right side

         C<em>₂H₅OH + __O₂ →  2CO₂ + __ H₂O</em>

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               ⇒ but only so far two on the right side

         C<em>₂H₅OH + __O₂ →  2CO₂ + 3H₂O</em>

  • On the right side of the equation, there are 7 oxygen molecules

                ⇒ but only so far three on the left side

         C<em>₂H₅OH + 3O₂ →  2CO₂ + 3H₂O</em>

<u>Let's check and make sure we got the answer:</u>

                           C<em>₂H₅OH + 3O₂ →  2CO₂ + 3H₂O</em>

<em>                 2 Carbon                ⇔                    2 Carbon</em>

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  ⇒ 1, 3, 2, 3

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#LearnwithBrainly<em>                      </em>

5 0
2 years ago
A 392 N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 24
alex41 [277]

Answer:

h=12.41m

Explanation:

N=392

r=0.6m

w=24 rad/s

I=0.8*m*r^{2}

So the weight of the wheel is the force N divide on the gravity and also can find momentum of inertia to determine the kinetic energy at motion

N=m*g\\m=\frac{N}{g}\\m=\frac{392N}{9.8\frac{m}{s^{2}}}

m=40kg

moment of inertia

M_{I}=0.8*40.0kg*(0.6m} )^{2}\\M_{I}=11.5 kg*m^{2}

Kinetic energy of the rotation motion

K_{r}=\frac{1}{2}*I*W^{2}\\K_{r}=\frac{1}{2}*11.52kg*m^{2}*(24\frac{rad}{s})^{2}\\K_{r}=3317.76J

Kinetic energy translational

K_{t}=\frac{1}{2}*m*v^{2}\\v=w*r\\v=24rad/s*0.6m=14.4 \frac{m}{s}\\K_{t}=\frac{1}{2}*40kg*(14.4\frac{m}{s})^{2}\\K_{t}=4147.2J

Total kinetic energy  

K=3317.79J+4147.2J\\K=7464.99J

Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height

K-W=E_{p}\\7464.99-2600J=m*g*h\\4864.99J=m*g*h\\h=\frac{4864.99J}{m*g}\\h=\frac{4864.99J}{392N}\\h=12.41m

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3 years ago
Which of the following statements are true? Select all correct responses. Choose all that apply. Choose all that apply. The tota
Ne4ueva [31]
<h3><u>Answer</u>;</h3>

-The total momentum of an isolated system is constant.

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<h3><u>Explanation</u>;</h3>
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3 years ago
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adoni [48]

Nice paddling.  Thanks for sharing.
Do you have some question to ask ?

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3 years ago
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