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Marat540 [252]
4 years ago
10

What is the linear separation D at the retina (micrometers)? The minimum diameter of the pupil is about 2 mm, the eye is most se

nsitive to wavelengths of about 500 nm (air), the index of refraction of the aqueous humor is n = 1.33, and the distance between the cornea and retina is about 2.5 cm.
Physics
1 answer:
Elis [28]4 years ago
3 0

Answer:

The linear separation at the retina is 5.725\times10^{-6}\ m

Explanation:

Given that,

Minimum diameter of the pupil = 2 mm

Wavelength = 500 nm

Index of refraction = 1.33

Distance between the cornea and retina = 2.5 cm

We need to calculate the angular separation

Using formula of angular separation

\alpha=1.22\times\dfrac{\lambda}{n d}

\alpha=1.22\times\dfrac{500\times10^{-9}}{1.33\times2\times10^{-3}}

\alpha=2.29\times10^{-4}

We need to calculate the linear separation at the retina

Using formula of linear separation

D=\alpha l

Put the value into the formula

D=2.29\times10^{-4}\times2.5\times10^{-2}

D=5.725\times10^{-6}\ m

Hence, The linear separation at the retina is 5.725\times10^{-6}\ m.

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