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3 years ago

Can someone pls help I’m stuck!

Physics

1 answer:

Elan Coil [88]3 years ago

6 0

B because why not i was wondering how ppl are so smart and let me tell ya i don’t know

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A ball rolls across the floor at a constant speed, what will happen to it if there is no friction?

Pepsi [2]

the ball will stay moving at the same rate of speed until something happens and stop it

7 0

3 years ago

What is the momentum of a bowling ball with mass of 8.9 kg and a speed of 6.0 m / s

PtichkaEL [24]

Answer:

The momentum of the bowling ball is 53.4 kg-m/s.

Explanation:

We have,

Mass of a bowling ball is 8.9 kg

Speed of the ball is 6 m/s

It is required to find the momentum of the ball. The momentum of an object is given in terms of its mass and speed as :

p = mv

$p=8.9\times 6\\\\p=53.4\ kg-m/s$

So, the momentum of the bowling ball is 53.4 kg-m/s.

7 0

4 years ago

Xenon has an enthalpy of vaporization of 12.6 kJ/mol and a vapor pressure of 1.00 atm at –108.0 °C. What is the vapor pressure o

earnstyle [38]

Answer:

P₁ = 0.0562 atm

Explanation:

Using the Clausius-Clapeyon equation

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁) ------ (eqn 1)

Step 1: From the question given, we state out the parameters given

P₁ = ? T₁ = -148.0⁰C

P₂ = 1atm T₂ = -108.0⁰C

ΔHvap = 12.6kJ/mol R = 8.314J/K.mol

Step 2: Do conversions where necessary for unit consistency since our R value is in J/K.mol

a) convert ⁰C to K

1K = ⁰C + 273.15

T₁ = -148.0⁰C => -148.0⁰C + 273.15

T₁ = 125.15K

T₂ = -108.0⁰C => -108.0⁰C + 273.15

T₂ = 166.15K

b) convert kJ/mol to Joules

ΔHvap = 12.6kJ/mol = 12600Joules

substituting parameters into eqn 1

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)

ln (P₁/1atm) = 12600J / 8.314 (1/166.15 - 1/125.15)

= 1515.51 (0.0060 - 0.0079)

= 1515.51(-0.0019)

ln (P₁/1atm) = -2.8794

taking exponential of both sides to get rid of the natural log

P₁ = e^ -2.8794

P₁ = 0.05616 atm

P₁ = 0.0562atm

Key Words

1) Clausius-Clapeyon: shows the relationship between pressure and temperature and it is used to estimate the vapour of a solution at a different temperature

5 0

3 years ago

Hey! anybody knows the answer then help me i will mark your answer!!!

Volgvan

10/9

Explanation:

option 2 is the correct answer

8 0

3 years ago

Find the density of a substance that has a volume of 754 cm3 and a mass of 7,917 grams. Don't forget your units!

Anit [1.1K]

Answer:

$\boxed{\sf Density \ of \ the \ substance = 10.5 \ g/cm^3}$

Given:

Mass (M) = 7917 grams

Volume (V)= 754 cm³

To Find:

Density of the substance

Explanation:

$\boxed{ \bold{\sf Density \ (\rho) = \frac{Mass \: (M)}{Volume \: (V)}}}$

Substituting values of M & V in the equation:

$\sf \implies \rho = \frac{7917}{754}$

$\sf \implies \rho = 10.5 \: g/ {cm}^{3}$

3 0

4 years ago