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lutik1710 [3]
3 years ago
6

An object is thrown downward from the top of a 175 meter building with an initial speed of 10m/s

Physics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

Explanation:

we can look for the final velocity of the object using the eqaution of motion as shown:

v² = u²+2gH

v is the  final velocity

u is the initial velocity = 10m/s

g is the acceleration due to gravity = 9.81m/s²

H is the height of the object = 175m

Subxtitute the given parameters inti the formula and get v:

v² = 10²+2(9.81)(175)

v² = 100+3433.5

v² = 3533.5

v = √3533.5

v = 59.44m/s

Hence the final velocity of the object is 59.44m/s

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If a roller coaster car had 40,000 J of gravitational potential energy when at rest on the top of a hill how much kinetic energy
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The potential energy of the roller coaster car, P.E = 40000 J

The kinetic energy at height h/4, K.E = ?

According to the law of conservation of energy, the total energy of the system is conserved.

At height 'h', the total energy is,

                                    P.E = mgh

                                     K.E = 0

At height 'h/4', the total energy is

                                     P.E + K.E = mgh

                                     P.E = mgh/4

                                     K.E = 1/2 mv²

Therefore,

                                   mgh/4 + 1/2 mv² = mgh

                                    gh/4 + v²/2 = gh

Hence,

                                      v² = 3gh/2

Substituting in the K.E equation

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                                       = 3/4 mgh

                                        = 3/4 x 40000

                                         = 30000 J

Hence, the K.E of the roller coaster car is, K.E = 30000 J

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