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vovikov84 [41]
3 years ago
9

Identify the role of each organism in the food chain.

Physics
2 answers:
Troyanec [42]3 years ago
5 0

Answer:

primary consumer, secondary consumer, tertiary consumer, producer, decomposer

Explanation:

the grass is the producer, the mushroom is the decomposer, the dragonfly is the primary consumer, the frog is the secondary, and the hawk is the tertiary consumer.

Stels [109]3 years ago
3 0

Answer:

If the dragonfly eats grass, the frog eats the dragon fly, the snake eats the frog, and the hawk the snake. That means:

dragonfly - consumer

frog - consumer

grass - producer

hawk - consumer

If the mushrooms decompose dead organisms. That means:

mushrooms - decomposer

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Which best describes the transition from gas to liquid?

gas is @ higher energy state than liq. so the transition must remove energy. so ans is  a. Energy must be removed because particles in liquid move more slowly.

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Which type of reactions usually happens slowest?
m_a_m_a [10]

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Which best explains the statement "It has no definite volume”?
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During a solar eclipse, the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational f
dezoksy [38]

Answer:

F= 2.3733 x10^{20} N

Explanation:

Let's define the variables to proceed with the operations,

So,

The masses

M_ {sun} = 1.99 * 10^{30} Kg

M_ {Earth} = 5.98 * 10 ^ {24} Kg

M_ {Moon} = 7.36 * 10 ^{22} Kg

Average distances

\bar {x} _ {Sun \rightarrow Earth} = 1.5 * 10 ^ {11} m

\bar {x} _ {Earth \rightarrow Moon} = 3.84 * 10 ^ 8m

Gravitational constant

G = 6.67 * 10^ {-11} \frac {Nm ^ 2} {kg ^ 2}

The formula of the Gravitational Force between the Moon and the Earth would be,

F = \frac {GM_ {Earth} M_ {Moon}} {(\bar {x} _ {Earth \rightarrow Moon}) ^ 2}

F= \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(5.98*10^{24}Kg)(7.36*10^{22}Kg)}{(3.84*10^8m)^2}

F = 1.9908 * 10 ^{20} N

This force is in the direction of the earth.

We perform the same process but now between the Sun and the Moon, like this,

F_2 = \frac {GM_ {Sun} M_ {Moon}} {(\bar {x} _ {Sun \rightarrow Earth} - \bar {x} _ {Earth \rightarrow Moon}) ^ 2}

F_2 = \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(1.99*10^{30}Kg)(7.36*10^{22}Kg)}{(1.5*10^{11}m-3.84*10^8m)^2}

F_2 = 4.3641*10^-{ 20} N

This force is in the direction of the Sun

The net force must be

F_ {net} = F_2-F

F_ {net} = 2.3733*10^{20} N

This in the direction of the Sun.

8 0
3 years ago
Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po
Lerok [7]

Answer:

h = 1.75 m

Explanation:

As we know that height of the slide is given as

h = 1.80 m

so time taken by the child to hit the water from the slide is given as

t = \sqrt{\frac{2h}{g}}

now we will plug all data in it

t = \sqrt{\frac{2(1.80)}{9.81}}

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now we know that the horizontal distance moved by it is given as

L = v_x t

3.55 = 0.605 v_x

v_x = 5.86 m/s

now by energy conservation

mgh = \frac{1}{2}mv^2

so height of point A is given as

h = \frac{v_x^2}{2g}

h = \frac{5.86^2}{2(9.81)}

h = 1.75 m

3 0
3 years ago
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