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zloy xaker [14]
2 years ago
11

a force is something that causes change in motion. what provides the force that made the cart speed up?

Physics
1 answer:
mihalych1998 [28]2 years ago
3 0
Either kinetic energy or a energy transformation of gravitational potential energy to kinetic energy or applied kinetic energy
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Which of following the smallest unit?(1) Electrons (2)Quarks (3)Neutrons (3)Protonus​
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quarks

Explanation:

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A sled slides down a hill with friction between the sled and hill but negligible alr resistance. Which of the following must be
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Answer:

A) The sum of the kinetic energy and the gravitational potential energy changes by an amount equal to the energy dissipated by friction,

Explanation:

  • The kinetic energy is the energy that the object has and is defied by the work that is needed to accelerate the body.
  • The gravitational potential is a mechanism by which an equal amount of energy is being transferred per unit mass that is needed for the object to move from the specific location.
  • Hence when the sled moves down the hill with the force of gravity it has negligible resistance as an equal amount of energy is dissipated.
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Pam is taking a train from the town of rome to the town of florence. rome is located 30 miles due west of the town of paris. flo
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<span>Since Florence is east, then Florence is 5 miles due west of Paris (30-25). Then, using the Pythagorean theorem with 45 miles as the length and 5 miles as the width, the square root of (45^2+5^2) is 45.277 miles.</span>
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3 years ago
A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h
Veronika [31]

Answer:

(A) Speed will be 44.18\times 10^4m/sec

(b) Change in kinetic energy = 1560\times 10^{-19}      

Explanation:

We have given mass of proton m=1.67\times 10^{-27}kg

Acceleration of the proton a=2.50\times 10^{12}m/sec^2

Initial velocity u = 1.60\times 10^4 m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

v^2=u^2+2as

v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039

v=44.18\times 10^4m/sec

(b) Initial kinetic energy KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2

Final kinetic energy KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2

So change in kinetic energy \Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J

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3 years ago
A symbolic model for learning is a model that is observed in person.
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Answer:

True

Explanation:

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