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yaroslaw [1]
3 years ago
7

An electron is fired horizontally at 2.5 x 10 m/s between two horizontal parallel plates 7.5 cm long, as shown in the diagram. T

he magnitude of the electric field is 130 N/C. The plate separation is great enough to allow the electron to escape. Edge effects and gravitation are negligible. Find the velocity of the electron as it escapes from between the plates.
Physics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

the answer to your question is 2.5

Explanation:

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A force of 50 n is exerted to the right on a 15 kg car at the same time a 30 n force is exerted to the left on the car. find the
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Find out what the force is and yiy have your answer
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4 years ago
It’s your birthday, and to celebrate you’re going to make your first bungee jump. You stand on a bridge 100 m above a raging riv
amm1812

Answer:

X'=50.4\,m

Explanation:

Given that:

Height of jump, h=100\,m

length of elastic cord, l=30\,m

spring constant of the cord, k=40\,N.m^{-1}

mass of the body that jumps, m=80\,kg

Force on the bungee elastic cord:

F=m.g

F=80\times 9.8

Now this force F will be responsible for the elongation in the elastic cord, so:

F=k.x ............................(1)

where :

k = spring constant

x = extension in the elastic cord

using eq. (1)

80\times 9.8=40\times x

x=19.6\,m

So the cord stretches 19.6 meters more beyond its original length of 30 meters.

Hence, the remaining distance from the river surface at the bottom is:

X'=100-(30+19.6)

X'=50.4\,m

3 0
3 years ago
A rock is pulled back in a slingshot as shown in the diagram below. The elastic on the slingshot is displaced 0.2 meters from it
irakobra [83]

Answer:

id

Explanation:

i don't know

4 0
3 years ago
Assume light is traveling through an optical medium of n1 and is incident on a boundary with a different optical medium with n2.
Elza [17]
That n2 = 2*n1.  That is, the index of refraction is twice as big in medium 2 since v=c/n
5 0
3 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
mariarad [96]

Answer:

d = 9.69 cm

Explanation:

given,

mass of the block = 1.2 Kg

spring force constant(k) = 730 N/m

spring is compressed = d = ?

rough patch width = 5 cm

μ_k = 0.44

work done by friction = energy lost

\mu_k mg \times x = \dfrac{1}{2}kd^2-\dfrac{1}{2}mv^2

0.44\times 1.2 \times 9.8 \times 0.05 = \dfrac{1}{2}\times 730 \times d^2-\dfrac{1}{2}\times 1.2 \times 2.3^2

3.432 = 365 d^2

d = \dfrac{3.432}{365}

d = 0.0969 m

d = 9.69 cm

5 0
3 years ago
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