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Brrunno [24]
3 years ago
11

Divide. Express the quotient in simplest form. x^2−x−12/2x^2÷x^2+x−6/2x^3

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
I strongly urge you to use parentheses here, to remove any ambiguity regarding which quantity is being divided by which quantity.  I'm assuming that you meant

(<span>x^2−x−12)/(2x^2)÷(x^2+x−6)/2x^3.  If that is correct, great.  If not, fix it!  Once correct, you can perform the divisions from left to right, beginning with (x^2-x-12)/2x^2.</span>
sertanlavr [38]3 years ago
5 0
Hey there!

These are technically expressed as fraction. When you divide a fraction by another, you can replace the second fraction with its reciprocal and you can now multiply the fractions together instead. 

\frac{x^2-x-12}{2x^2} /  \frac{x^2+x-6}{2x^3}

\frac{x^2-x-12}{2x^2} * \frac{2x^3}{x^2+x-6}

Now, just multiply across the top and the bottom. You can first cancel out any terms that are repeated or similar. 

\frac{12}{2x^2} * \frac{2x^3}{-6}

\frac{2}{x} * \frac{1}{-1}

\frac{2}{-x}

Your answer will be \frac{2}{-x}. 

Hope this helped you out! :-)
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\:

Step-by-step explanation:

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\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{  \: Circumference_{(circle)}= 2 \pi r}}}}}} \: \: \bigstar \\ \\

Where

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Now substituting the values in the formula :

\\{ \longrightarrow \qquad{  {{\sf{{  \: Circumference_{(circle)}= 2  \times 3.14 \times  8}}}}}} \: \:  \\ \\

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