Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers per hou
r less than the other's. If they meet in 3 hours, what is the rate of the slower car
1 answer:
Answer:
70 km/h
Explanation:
Let the velocity of car A is v km/h, thus the velocity of car B is (v - 20) km/h.
They meet after 3 hours.
Distance traveled by car A in 3 hours = v x 3 = 3 v
Distance traveled by car B in 3 hours = (v - 20) x 3 = 3v - 60
Total distance traveled is 480 km
So, 3 v + 3 v - 60 = 480
6 v - 60 = 480
6 v = 540
v = 90 km/h
Thus, the speed of car A is 90 km/h and the speed of car B is 90 - 20 = 70 km/h.
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The sound of a lamb is <u>grave </u>due to its <u>high </u>pitch depending on its <u>low </u>frequency. Option B is correct.
<h3>What is the frequency of the sound?</h3>A sound pressure wave's frequency is the number of times it repeats itself every second.
The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.
Pitch and the frequency of sound are inverse to each other. A lamb's sound is grave because of its high pitch and low frequency.
The sound of a lamb is <u>grave </u>due to its <u>high </u>pitch depending on its <u>low </u>frequency.
Hence, option B is correct.
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Answer:
Option b
Solution:
As per the question:
Speed of the mouse, v = 1.3 m/s
Speed of the cat, v' = 2.5 m/s
Angle,
Now,
To calculate the distance between the mouse and the cat:
The distance that the cat moved is given by:
The position of the cat and the mouse can be given by:
x' = 0.67 t (1)
The initial speed of the cat ahead of the mouse:
u =
When the time is 0.5t, the speed of the cat is 0, thus:
Substituting the value of t in eqn (1):
x' = 0.67(0.314) = 0.210 m
Thus the distance comes out to be 0.210 m