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3 years ago

Justify why does a bird flap its wing to fly higher??

Physics

1 answer:

SpyIntel [72]3 years ago

8 0

Answer:

they use thermals and air currents to glide.

Explanation:

when they flap higher they use thermals and air currents because flapping takes a lot of fuel,energy

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Light from a helium-neon laser (? = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a sc

Sladkaya [172]

Answer:

0.3376 mm

Explanation:

The computation of the spacing in mm between the slits is shown below:

As we know that

$d = \frac{m\lambda L}{\Delta y}$

where,

$\lambda$ = wavelength

L = distance from the scrren

$\Delta y$ = spanning distance

As there are 11 bright fingers seen so m would be

= 11 - 1

= 10

Now placing these values to the above formula

So, the spacing is

$= \frac{(10)(633 \times 10^{-9})(3.2m)}{60 \times 10^{-3}}$

= 0.3376 mm

We simply applied the above formula.

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3 years ago

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Which characteristics is common in mature rivers river

amm1812

It channels erode wider fed by many tributaries and has more discharge and is less steep

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3 years ago

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A bin is given a push across a horizontal surface. The bin has a mass m, the push gives it an initial speed of 1.60 m/s, and the

emmasim [6.3K]

Answer:

The bin moves 0.87 m before it stops.

Explanation:

If we analyze the situation and apply the law of conservation of energy to this case, we get:

Energy Dissipated through Friction = Change in Kinetic Energy of Bin (Loss)

F d = (0.5)(m)(Vi² - Vf²)

where,

F = Frictional Force = μR

but, R = Normal Reaction = Weight of Bin = mg

Therefore, F = μmg

Hence, the equation becomes:

μmg d = (0.5)(m)(Vi² - Vf²)

μg d = (0.5)(Vi² - Vf²)

d = (0.5)(Vi² - Vf²)/μg

where,

Vf = Final Velocity = 0 m/s (Since, bin finally stops)

Vi = Initial Velocity = 1.6 m/s

μ = coefficient of kinetic friction = 0.15

g = 9.8 m/s²

d = distance moved by bin before coming to stop = ?

Therefore,

d = (0.5)[(1.6 m/s)² - (0 m/s)²]/(0.15)(9.8 m/s²)

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3 years ago

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

irinina [24]

Answer:

Coil 2 have 235 loops

Explanation:

Given

The number of loops in coil 1 is n ₁= 159

The emf induced in coil 1 is ε ₁ = 2.78 V

The emf induced in coil 2 is ε ₂ = 4.11 V

Let

n ₂ is the number of loops in coil 2.

Given, the emf in a single loop in two coils are same. That is,

ϕ ₁/n ₁= ϕ ₂ n ₂⟹ 2.78/159 = 4.11/ n ₂

n₂= $\frac{159 * 4.11}{2.78}$

n₂=235

Therefore, the coil 2 has n ₂= 235 loops.

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Pressure, V is volume , T is temperature of a gas and R is gas constant.

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3 years ago

Justify why does a bird flap its wing to fly higher??​

Justify why does a bird flap its wing to fly higher??