Answer:
The wavelength of the 320 Hz sound waves in the column of air is 1070 mm.
Explanation:
To solve the question, we note that the tube acts as a pipe with one end closed and that a stationary wave is formed in the tube from the top, to the bottom of the tube and back.
The simplest and the first wave form in the tube has length L = Lambda/4
That is, a node at the closed end and an antinode at the open end
The second stationary wave is given by
l + 535 mm= 3/4×lambda
However v = f×lambda
f = v/lambda = v/(4l)
Therefore
Lambda/4 + 535 mm = 3/4lambda
Or 535 mm = 3/4lambda -Lambda/4 = lambda/2
Therefore, lambda = 2×535 mm = 1070 mm
The wavelength = 1070 mm
Answer:
Sorry but don't know how to calculate velocity
Explanation:
Index of refraction can be calculated using the following formula:
where in a vacuum and "n" is the index of refraction. So we must calculate our velocity by manipulating the index of refraction formula and isolate v and so:
We could go one by one and calculate the velocity or use logic. If you divide by a larger number the output will be a smaller number. Therefore, the answer would be n=1.62 is the slowest.
By that logic when n=1 light would travel the fastest of these four scenarios. The key thing to understand about these problems is that the speed of light slows down as it goes through a medium, in a vacuum it's 3 x 10^ 8 m/s but as it goes through say air or water light slows down.