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storchak [24]
2 years ago
8

An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?

Chemistry
1 answer:
julsineya [31]2 years ago
3 0

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

Learn more about density:

brainly.com/question/952755

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The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of
lianna [129]

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2     (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

8 0
3 years ago
In a solution, what term is given to the liquid?
Jet001 [13]

Answer: solvent

solvent is  A solvent is usually a liquid

7 0
3 years ago
Read 2 more answers
2. STEM The mass of an atom of helium is about 4.002 atomic units.
Anit [1.1K]

Answer:

The approximate mass of beryllium is 9.0045 u.

Explanation:

Given data:

mass of helium= 4.002 u

mass of beryllium which is 2.25 times of mass of helium= ?

Solution:

we will multiply the mass of helium with 2.25 times,

4.002 u × 2.25 = 9.0045 u

so the mass of beryllium atom would be 9.0045 u.

6 0
3 years ago
What is the mass of 1.75 moles of magnesium atoms
Artemon [7]

Hey there!

Molar mass of magnesium is 24.305.

One mole of magnesium has a mass of 24.305 grams.

We have 1.75 moles.

Multiply 1.75 by 24.305.

1.75 x 24.305 = 42.5

1.75 moles of magnesium has a mass of 42.5 grams.

Hope this helps!

6 0
3 years ago
All of the following equations are statements of the ideal gas law except
evablogger [386]

Answer:

  • The first equation, <em>a. PV = nRT</em>, <u>is not</u> <em>a valid statement of the ideal gas law.</em>

Explanation:

The basic expression for the<em> ideal gas law</em> is:

  • pV=nRT      .......... [Equation 1]

Where:

  • n is the number of moles of the gas
  • V is the volume occupied by the gas
  • p is the pressure exerted by the gas molecules
  • T is the temperature in absolute scale (Kelvin)
  • R is the Universal gas constant (0.0821 atm-liter /K-mol or the equivalents in other units)

You can perform different algebraic operations to obtain equivalent equations:

<u>Choice b) Divide equation 1 by T and you get</u>:

  • pV / T = nR, which is the choice b. from your list.

<u>Choice c) Divide equation 1 by n × V and you get</u>:

  • p/n = RT / V, which is the choice c. from your list.

<u>Choice d) Divide equation 1  n × T and you get</u>:

  • pV / (nT) = R, which is the choice d. from your list.

The choice a. p = nRTV states that p and V are in direct relation, when the ideal gas law states that p and V are inversely related, so that equation is wrong.

<u>Conclusion: </u>the choice a, p = nRTV, is not a statement of the ideal gas law.

3 0
3 years ago
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