The most abundant isotope is Gz-83 because the average atomic mass of Gz is closer to 83.
The average atomic mass is defined as the weigthed mean of the isotopes.
The mass of the isotopes is 80, 81 and 83 uma, respectively.
As the average atomic mass (82.74uma) is closer to the atomic mass of Gz-83 than the mass of the other isotopes, you can interpretate that the most abundant isotope is Gz-83.
Learn more about average atomic mass in:
brainly.com/question/21536220
<u>We are given:</u>
Mass of water: 119 grams
We know that one mole of a gas occupies 22.4L of volume
<u>Number of moles of water:</u>
Number of moles = given mass / Molar mass
Number of moles = 119 / 18 [molar mass of water = 18 grams/mol]
Number of moles = 6.61 moles
<u>Volume occupied:</u>
Volume = number of moles * 22.4 L
Volume = 6.61 * 22.4
Volume = 148L
Volume (in mL) = 1.48 * 10⁻¹ mL
Answer:
Zn(s) + Fe(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Fe(s)
Explanation:
When metal zinc is added to an iron (II) nitrate solution, we can see the following redox reaction:
Zn(s) + Fe(NO₃)₂(aq) ⇒ Zn(NO₃)₂(aq) + Fe(s)
Zinc is oxidized since its oxidation number increases from 0 to +2.
Iron is reduced since its oxidation number decreases from +2 to 0.
Answer:- Mass of the titanium alloy is 7.01 g, choice C is correct.
Solution:- The heat of fusion is given as 422.5 joules per gram and it also says that 2960 joules of heat is required to melt the metal completely.
The suggested equation is, 
where Q is the heat energy, m is the mass and Hf is the heat of fusion.
Since, we are asked to calculate the mass, the equation could be written as:
Let's plug in the values in it:
m = 7.01 g
So, the mass of the titanium alloy is 7.01 g, choice C is correct.
Answer:
The correct answer is 187.7 J/Jg.
Explanation:
The formula for finding the specific heat of fusion is,
Specific heat of fusion = Q/m
Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.
Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg
Now putting the values in the formula we get,
Specific heat of fusion = Q/m
Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg
