All categories

3 years ago

Why is it important to have evidence to support conclusions? What is the impact of using weak or inaccurate evidence? describe a

Chemistry

1 answer:

dem82 [27]3 years ago

7 0

Answer:

Evidence is important when it comes to persuading people or providing a certain point. This applies to a work piece such as an essay, report, etc... If you have weak evidence, then people wouldn't be strongly convinced or persuaded by your point. For instance: In court, it is very important to have evidence inorder for the judge to decide whether the person will be guilty or innocent.

You might be interested in

What is the advantage of seeds that can be spread over a wide area?

Tema [17]

Answer:

I'm fairly sure it's D

Explanation:

If they're more spread out than they're roots in theory should have more space. Sorry if I'm wrong

6 0

3 years ago

The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10

Sati [7]

Answer:

a. 113 min

Explanation:

Considering the equilibrium:-

2N₂O₅ ⇔ 4NO₂ + O₂

At t = 0 125 kPa

At t = teq 125 - 2x 4x x

Thus, total pressure = 125 - 2x + 4x + x = 125 - 3x

125 - 3x = 176 kPa

x = 17 kPa

Remaining pressure of N₂O₅ = 125 - 2*17 kPa = 91 kPa

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = $2.8\times 10^{-3}$ min⁻¹

Initial concentration $[A_0]$ = 125 kPa

Final concentration $[A_t]$ = 91 kPa

Time = ?

Applying in the above equation, we get that:-

$91=125e^{-2.8\times 10^{-3}\times t}$

$125e^{-2.8\times \:10^{-3}t}=91$

$-2.8\times \:10^{-3}t=\ln \left(\frac{91}{125}\right)$

$t=113\ min$

3 0

3 years ago

What scientific instrument is sensitive enough to detect a planet transiting a star?

Stolb23 [73]

The correct scientific instrument is telescope.

5 0

3 years ago

The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.

maw [93]

CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial Y - -
Change -X +X +X
Equilibrium Y-X X X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
= 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
= 5.79 x 10⁻³ g/L

7 0

3 years ago

Which of the following will produce a precipitate?

nekit [7.7K]

Reaction of option c produces precipitate.

Rhodium on reacting with potassium phosphate produces rhodium phosphate which remain in solution due to low lattice energy for rhodium phosphate.

Niobium on reacting with lithium carbonate produces niobium carbonate and it will remain in aqueous form.

Cobalt on reacting with zinc nitrate produces cobalt nitrate. This, Co(NO3 )2 is insoluble precipitate and settles at bottom whereas zinc ion will remain in solution as follows:

$Co^2^+ + Zn(NO¬_3 )¬_2 Co(NO¬_3 )¬_2 + Zn^2^+$

Potassium ion on reacting with sodium sulfide produces potassium sulfide which remain in solution

8 0

3 years ago