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attashe74 [19]
2 years ago
11

I need help with this math problem!

Mathematics
2 answers:
Stolb23 [73]2 years ago
6 0

Answer:

C and E

Step-by-step explanation:

Alex Ar [27]2 years ago
3 0

Answer:

I believe that the answer is

C and E

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Jeremy raised $250 for charity last year. This year he raised 20% more than he raised last year. How much money did Jeremy raise
Lesechka [4]
You would find this by doing 250 times 20% which is .2 and you would get 50 so you would add 250 plus 50 and get 300.
The answer is $300
5 0
3 years ago
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100 points please help 8th grade math
Irina-Kira [14]

Answer:B? l hope is B l hope helps

Step-by-step explanation:

if not help then l will answer other problem from you l hope is right

7 0
3 years ago
How can you generate x-3y+5 from the expression x+y+4+2y+1
vladimir2022 [97]

Answer: Here is the explanation. also it it +3y not -3y

Step-by-step explanation:

x+y+4+2y+1=x+3y+5 because

2y+y=3y

so now you have x+3y+4+1

4+1=5

now you have: x+3y+5

if you do not understand, What i am trying to say is, you need to add all of the same things.

3 0
3 years ago
On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
Read 2 more answers
Wholesale price: $12.75<br> Percent markup: 40%
Ilia_Sergeevich [38]

Answer:

17.85

Step-by-step explanation:

12.75 multiplied by .40 = 5.10

5.10 + 12.75 = 17.85

4 0
3 years ago
Read 2 more answers
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