The question is incomplete,the complete question :
Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the density of the solution is needed to solve the problem
Answer:
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Explanation:
10.0% (by mass) aqueous solution of hydrochloric acid.
10 grams of HCl is present in 100 g of solution.
Mass of HCl = 10 g
Mass of solution = 100 g
Mass of solution = Mass of solute + Mass of water
Mass of water = 100 g - 10 g = 90 g
Moles of HCl = 
Mass of water in kilograms = 0.090 kg
Molality = 
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
wrong it was E. Evaporation of water if your on plato btw
BRAINLY!!!!
Curium (Cm, 96) – Pierre and Marie Curie einsteinium (Es, 99) – Albert Einsteinfermium (Fm, 100) – Enrico Fermigallium (Ga, 31) – both named after Gallia (Latin for France) and its discoverer, Lecoq de Boisbaudran (le coq, the French word for 'rooster' translates to gallus in Latin)hahnium (105) – Otto Hahn (Dubnium, named for Dubna in Russia, is the IUPAC-accepted name for element 105)lawrencium (Lr, 103) – Ernest Lawrencemeitnerium (Mt, 109) – Lise Meitner<span>mendelevium (Md, 101) – Dmitri Mende</span>
<span>obelium (No, 102) – Alfred Nobel<span>roentgenium (Rg, 111) – Wilhelm Roentgen (formerly Ununumium)</span><span>rutherfordium (Rf, 104) – Ernest Rutherford </span><span>seaborgium (Sg, 106) – Glenn T. Seaborg</span></span>
To answer this question, you need to know the chemical equation for making glucose. It should be look like this
C6H12O6<span>(s) + 6O2(g) -->6CO2(g) + 6H2O(g)
In the equation, the amount of glucose (</span>C6H12O6) is 1 and the amount of oxygen(O2) is 6. But the equation ratio is using moles as a unit. A mole of glucose will weight 180g but a mole of oxygen weight 32g.
Then, the amount of oxygen forms would be: 6/1 * (15.90g/180g) * 32g= 16.96 grams
Answer:
Some G proteins activate adenylate cyclase, while others inhibit it.
Explanation:
G proteins helps in the signal transduction process that transfer message in the body. GPCRs (G-protein-coupled receptors) are located on the surface membrane of the cell.
The G protein can activates the protein or might deactivate the proteins that helps in the adenylate cyclase. The particular phosphorylation and dephosphorylation process at different sites by the G proteins can result in activation and inactivation of adenylate cyclase.
Thus, the correct answer is option (C).
