All categories

3 years ago

How much kg is equal to what g

Chemistry

1 answer:

Marizza181 [45]3 years ago

6 0

Answer:

1kg= 1000 grams hope it helps

You might be interested in

2.20 moles Sn to grams

mihalych1998 [28]

261.162 grams. Use the equation n=M÷Mr.

3 0

3 years ago

The surface of water can act like a sort of skin due to a property of liquids called

stiv31 [10]

Surface tension ..viscosity is the thickness of a liquid, doesn't fit here...condensation and evaporation are processes not properties.

8 0

3 years ago

Read 2 more answers

Neon doesn't take part in chemical reaction why give reason

ankoles [38]

Neon has filled its outer shells, therefore it is very stable and does not need to react with other elements and doesn’t form compounds.

5 0

3 years ago

Read 2 more answers

A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from

sweet-ann [11.9K]

Answer:

$T_i~=163.1$ ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

Initial temperature of gold= Unknow

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the heat equation:

$Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT$

$Q_A_u=m_A_u*Cp_A_u*deltaT$

We can relate these equations if we take into account that all heat of gold is transfer to the water, so:

$m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT$

Now we can put the values into the equation:

$60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)$

Now we can solve for the initial temperature of gold, so:

$T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20$

$T_i~=163.1$ ºC

I hope it helps!

5 0

3 years ago

What is the affect of this

Alisiya [41]

Answer:

Explanation:

Your answer should be in the attached pdf

Download pdf

5 0

3 years ago

Read 2 more answers