3 years ago

How much kg is equal to what g

Chemistry

1 answer:

Marizza181 [45]3 years ago

6 0

Answer:

1kg= 1000 grams hope it helps

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Be sure to answer all parts.The equilibrium constant (Kc) for the formation of nitrosyl chloride, an orange-yellow compound, fro

miss Akunina [59]

Explanation:

Since, the given reaction is as follows.

$2NO(g) + Cl_{2} \rightleftharpoons 2NOCl$

Expression for $Q_{c}$ of this reaction is as follows.

$Q_{c} = \frac{[NOCl]^{2}}{[NO]^{2}[Cl_{2}]}$

Putting the given values into the above formula as follows.

$Q_{c} = \frac{[NOCl]^{2}}{[NO]^{2}[Cl_{2}]}$

= $\frac{(9.50)^{2}}{(4.40 \times 10^{-2})^{2} \times (1.80 \times 10^{-3})}$

= $\frac{90.25}{34.848 \times 10^{-7}}$

= $2.59 \times 10^{-7}$

Thus, we can conclude that $Q_{c}$ for the experiment is $2.59 \times 10^{-7}$ .

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3 years ago

PLEASE PLEASE HELP<br> Calculate the mass of 3.4 moles of nitric acid (HNO3)

Elza [17]

Molar mass of nitric acid (HNO3) =atomic mass of hydrogen + atomic mass of nitrogen +3x atomic mass of oxygen . The molar mass of nitric acid (HNO3) is 63.0144 gram per mole, but you have 3.4 moles. Therefore; the answer is 63.0144 g/mole x 3.4 moles = 214.24896 grams.

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3 years ago

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harkovskaia [24]

I think the answer is C , more dense

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3 years ago

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What is the percent composition of oxygen in CsHSO2<br>

Otrada [13]

Answer:

72.71 %

Explanation:

CO2. % C = 12.01/44.01 = 0.2729= 27.29% (we will divide 0.2729 with 100 to take the percentage). % O = 32.00/44.01 =0.7271 =72.71 %O in CO2.

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3 years ago