Answer:
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Explanation:
Answer:
802.2 K
Explanation:
To solve this problem we can use the formula:
Where Tb is the boiling point (in K).
We already know the values of both ΔHvap and ΔSvap, so we calculate Tb:
- ΔHvap = 47.45 kJ·mol⁻¹ = 47.45x10³J·mol⁻¹
Tb = 47.45x10³J·mol⁻¹/59.15 J·mol⁻¹·K⁻¹
So the boiling point of the compound is 802.2 K (or 529 °C)
Becuase they have water and oxygen carbon dioxide in them
Answer:
your answer second once is correct
Explanation:
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Answer:
The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451
Explanation:
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