2 high tides and 2 low tides. hope that helped
The answer is oxidation.
That is in the redox fueling reaction,
succinate + NAD ↔fumarate + NADPH, the succinate molecule is undergoing oxidation.
As succinate molecule is providing electrons to NAD, so that it can be reduced from NAD to NADPH. So it is losing electrons and undergoing oxidation.
So the answer is oxidation.
<span>Fischer projection for D-2-ketotetrose is in Word document below.
</span>D-2-ketotetrose is monosaccharide, having both a ketone (a ketose) and four carbons (a tetrose). There are two ketotetroses (the enantiomers) L and D-erythrulose, this is D-erytrhrulose (1,3,4-trihydroxy-2-butanone).
The <span>Fischer projection is </span>two-dimensional<span> representation of a </span>three dimensional organic molecule.
<span>C. In order for a nonmetal to obey the octet rule, it gains electrons.</span>
