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weqwewe [10]
3 years ago
10

How do scientist communicate the results of an investigation?​

Chemistry
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:money

Explanation:

maks197457 [2]3 years ago
5 0

Answer:

scientists often communicate their research results in three general ways:

1) One is to publish their results in peer-reviewed journals that can be ready by other scientists.

2) Two is to present their results at national and international conferences where other scientists can listen to presentations

Explanation:

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A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
maw [93]

Answer:

1.3223 acres

Explanation:

a football field's area is 360 feet (120 yards) x 160 feet (53.333 yards) = 57,600 sq. feet

if the area of an acre is 43,560 sq. feet, then a football field in acres = 57,600 sq. feet / 43,560 sq. feet = 1.3223 acres

we can verify our answer by doing the same calculation in sq. yards:

football field = 120 yards x 53.33 yards = 6,400 sq. yards

an acre is 4,840 sq. yards

football field in acres = 6,400 sq. yards / 4,840 sq. yards = 1.3223 acres

8 0
3 years ago
Read 2 more answers
The enzyme, phosphoglucomutase, catalyzes the interconversion
Fittoniya [83]

Answer:

K_{eq = 19

ΔG° of the reaction forming glucose 6-phosphate =  -7295.06 J

ΔG° of the reaction  under cellular conditions = 10817.46 J

Explanation:

Glucose 1-phosphate     ⇄     Glucose 6-phosphate

Given that: at equilibrium, 95% glucose 6-phospate is  present, that implies that we 5% for glucose 1-phosphate

So, the equilibrium constant K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq= \frac{0.95}{0.05}

K_{eq = 19

The formula for calculating ΔG° is shown below as:

ΔG° = - RTinK

ΔG° = - (8.314 Jmol⁻¹ k⁻¹ × 298 k ×  1n(19))

ΔG° = 7295.05957 J

ΔG°≅ - 7295.06 J

b)

Given that; the concentration  for  glucose 1-phosphate = 1.090 x 10⁻² M

the concentration of glucose 6-phosphate is 1.395 x 10⁻⁴ M

Equilibrium constant  K_{eq can be calculated as:

K_{eq = \frac{[glucose-6-phosphate]}{[glucose-1-[phosphate]}

K_{eq}= \frac{1.395*10^{-4}}{1.090*10^{-2}}

K_{eq} = 0.01279816514  M

K_{eq} = 0.0127 M

ΔG° = - RTinK

ΔG° = -(8.314*298*In(0.0127)

ΔG° = 10817.45913 J

ΔG° = 10817.46 J

5 0
3 years ago
Match each pH value with the correct description. 7, 2, 8, 13, and 6 :)
bazaltina [42]
1.strong acid: 2
2.weak acid:6
3.strong base:13
4.weak base:8
5.neutral:7
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3 years ago
What is important info about FOOD inc.
IgorLugansk [536]

Food, Inc. is a 2008 American documentary film directed by Robert Kenner and narrated by Michael Pollan and Eric Schlosser. It examines corporate farming in the United States, concluding that agribusiness produces food that is unhealthy in a way that is environmentally harmful and abusive of both animals and employees

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1 year ago
HELP!!! I need "2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)" in word form
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I don’t get it what do u need exactly?
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