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oee [108]
4 years ago
11

To which planet do scientist compare to Kepler-10

Chemistry
1 answer:
Stells [14]4 years ago
7 0
To Earth, since it has the same radio and masses. This is what I believe.
You might be interested in
Consider two equal-volume flasks of gas at the same temperature and pressure. One gas, oxygen, has a molecular mass of 32. The o
san4es73 [151]

Answer: The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

Explanation:

According to avogadro's law, equal volumes of all gases at same temperature and pressure have equal number of moles.

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus as oxygen and nitrogen are at same temperature and pressure and are in equal volume flasks , they have same number of moles and thus have same number of molecules.

The ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks is 1: 1

3 0
3 years ago
How do you do this?
Alona [7]
It would be Atom 2 because the proton and neutron are both nine and the election is 8 which is -1 to nine <span />
7 0
3 years ago
What does the symbol (–Delta.Hfus) indicate in a phase change?
Rufina [12.5K]

Answer:

changes from a solid to a liquid

Explanation:

8 0
3 years ago
Name this compound Cr2(CO3)3
kiruha [24]

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

5 0
3 years ago
What are the missing coefficents for the following equation? __N2+__H2-&gt;__NH3
vivado [14]

Answer:

1, 3, 2

Explanation:

N2 + H2 → NH3

I usually find that the best way to systematically balance an equation by inspection is to start with the most complicated-looking formula and then balance atoms in the order:

  1. All atoms other than O and H
  2. O
  3. H

(a) The most complicated formula is NH3.

(b) Balance N.

We have 1 H in NH3, but 2 N on the left. We need 2 N on the right. Put a 1 in front of N2 and a 2 in front of NH3.

1N2 + H2 → 2NH3

(c) Balance H.

We have fixed 6 H on the right, so we need 6 H on the left. Put a 3 in front of H2.

1N2 + 3H2 → 2NH3

The equation is now balanced, and the coefficients are 1, 3, 2.

5 0
3 years ago
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