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harkovskaia [24]
3 years ago
7

A 126.1-gram block of granite at 92.6°C is dropped into a tub of water at 24.7°C in an isolated system. The final temperature of

both the granite and the water is 51.9°C. The specific heat capacity of granite is 0.795 joules/gram degree Celsius, and the specific heat capacity of water is 4.186 joules/gram degree Celsius.
The granite block transferred 1.____ of energy, and the mass of the water is 2.____ .Copy


1
A. 21,500 joules
B. 6,810 joules
C. 4,080 joulesCopy


2
A. 189 grams
B. 55.8 grams.
C. 35.8 grams
Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

The granite block transferred <u>4080 J</u> of energy, and the mass of the water is <u>35.8 g</u>.

1. <em>Energy from granite block </em>

The formula for the heat (<em>q</em>) transferred is

<em>q = mC</em>Δ<em>T</em>

<em>m</em> = 126.1 g; <em>C</em> = 0.795 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C - 92.6 °C = -40.7 °C

∴ <em>q</em> = 126.1 g × 0.795 J·°C⁻¹g⁻¹ × (-40.7 °C) = -4080 J

The granite block transferred 4080 J.

2. <em>Mass of water </em>

<em>q = mC</em>Δ<em>T </em>

<em>m = q</em>/(<em>C</em>Δ<em>T</em>)

<em>q </em>= 4080 J; <em>C</em> = 4.186 J·°C⁻¹g⁻¹; Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 51.9 °C – 24.7 °C = 27.2 °C

∴ <em>m</em> = 4080 J/(4.186 J·°C⁻¹g⁻¹ × 27.2 °C) = 35.8 g

The mass of the water is 35.8 g.

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<h3>How to calculate mass?</h3>

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